Question

Write an equation of a line in point-slope, slope-intercept, and standard form that has

Answer 1

Answer:

(a) $y + 4x - 14 = 0$

(b) $y = -4x + 14$

(c) $y + 4x = 14$

Step-by-step explanation:

The formula for calculating the equation of line in point - slope form is given as :

$y-y_{1} = m(x-x_{1} )$

where m is the slope

Given from the question :

m = - 4

$x_{1}$ = 2

$y_{1}$ = 6

Substituting into the formula , we have :

$y - 6 = - 4(x - 2)$

$y - 6 = -4x + 8$

$y + 4x - 6 - 8 = 0$

$y + 4x - 14 = 0$

Therefore :

(a) the equation of the line in point - slope form is $y + 4x - 14 = 0$

(b) to write it in slope - intercept form , we will make y the subject of the formula , which will give : $y = -4x + 14$

(c) the equation of line in standard form is ; $y + 4x = 14$