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3 years ago

45 + 57 = x + y x= 37 y =?

Mathematics

2 answers:

Umnica [9.8K]3 years ago

7 0

Hey!

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Solution:

~Substitute

45 + 57 = 37 + y

~Subtract y to both sides

45 + 57 - y = 37 + y - y

~Simplify

102 - y = 37

~Subtract 102 to both sides

102 - y - 102 = 102 - 37

~Simplify

y = 65

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Answer:

y = 65

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Hope This Helped! Good Luck!

Mekhanik [1.2K]3 years ago

5 0

Answer:

y = 65

Step-by-step explanation:

45 + 57 = x + y

x = 37

45 + 57 = 37 + y

45 + 57 = 102

102 = 37 + y

-37 -37

102 - 37 = 65

37 + y - 37 = y

65 = y

y = 65

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2 years ago

Show both decimal places (5.06).

lilavasa [31]

a. the cost of a call for six minutes is 0.70.

b.the cost of a 14-minute call is 2.62.

c.the cost of a 9 ½2-minute call is 1.66.

given that

rate schedule for an m-minute call from any of its pay phones 0.70.

c(m) = 0.70 when m<=6

c(m) = 0.70+ 0.24(m-6) when m>6 & m is an integer

c(m) = 0.70+0.24((m-6)+1) when m>6 & m is not an integer.

a. to find the cost of a call for six minutes.

already given that c(m) =0.70 when m=6.

Therefore, the cost of a call for six minutes is 0.70.

b. to find the cost of a 14-minute call.

according to given information

$c(14) = 0.70 + 0.24(m - 6) \\ c(14) = 0.70 + 0.24(14 \: - 6) \\c(14) = 0.70 + (0.24 \times 14) - (0.24 \times 6) \\c(14) = 0.70 + (3.36 - 1.44) \\ c(14) = 0.70 + 1.92 \\ c(14) = 2.62$

Therefore,the cost of a 14-minute call is 2.62.

c.to find the cost of a 9 ½2-minute call

according to given information

$c(9 \frac{1}{2} 2) = 0.70 + 0.24((9 \frac{1}{2} 2 - 6) + 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24((9 - 6) + 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24(3+ 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24(4) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.96 \\ c(9 \frac{1}{2} 2) = 1.66$