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hammer [34]
3 years ago
6

Which trait did the Northeast Woodland Indians have in common with the Southeast Indians? A. The economy was largely based on ag

riculture. B. Common meals included alligator meat. C. Houses typically contained multiple rooms. D. Wampum belts were popular trading items. E. Dwellings contained beehive-shaped roofs.
Mathematics
2 answers:
astraxan [27]3 years ago
8 0

Answer:

the answer is a.

Step-by-step explanation:

natka813 [3]3 years ago
5 0
The answer is A, the economy was largely based on agriculture.
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A volcano in the approximate shape of a cone has a diameter of 16 km and a height of 1.95 km.
makkiz [27]
The answer should be 130km^2
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3 years ago
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One day Mr. Pritz drove for 6 1/3 hours. The next day he drove 9 1/2 hours. For how many hours did he drive during the two days?
maks197457 [2]

Answer:

Step-by-step explanation:

First convert them into improper fractions: 6\frac{1}{3} =\frac{19}{3} and 9\frac{1}{2} =\frac{19}{2}. Now we add: \frac{19}{2}+\frac{19}{3}=\frac{95}{6} or 15\frac{5}{6}.

7 0
3 years ago
How do you find 4t-4=48
Xelga [282]

11

Step-by-step explanation:

subtract 4 from 48 which gives you 44

then divide 4 by 44 to leave t alone

that would give you 11

t equals 11

5 0
3 years ago
4x + 5 = 6x - 11<br> 1.6<br> 0-8<br> 0.6<br> 8
Svet_ta [14]
8 calculate the problem and you get your answer :)
3 0
3 years ago
Read 2 more answers
I honestly don’t get how to solve this
ruslelena [56]

Answer:

Two other possible measure ments of AD and AE are

(a)  Let AD = 4 units  and AE = 6 units.

(b )Let AD = 2 units  and AE = 3 units,

Step-by-step explanation:

In ΔABC, given

AB = 8 units,    BC  = 9 units,           AC = 12 units,

D is on AB       and   E is on AC

Now, when AD = 6 and AE = 9, both  ΔABC and ΔADE are similar.

Also, DB = 8 units - 6 units  = 2 units,

        EC = 12 units - 9 units   =  3 units

⇒\frac{AD}{DB}  = \frac{AE}{EC}  =  3

To adjust the points D and E in such a way,  triangles REMAIN SIMILAR.

(a)  Let AD = 4 units  and AE = 6 units

  Then,  DB = 8 units -  4 units  = 4 units,

              EC = 12 units - 6 units   =  6 units

⇒\frac{AD}{DB}  =  \frac{4}{4} = 1 ,  \\ \frac{AE}{EC}  =    \frac{6}{6}   = 1

⇒\frac{AD}{DB}  =  \frac{AE}{EC}  = 1

Hence,   ΔABC and ΔADE are similar.

(b)  Let AD = 2 units  and AE = 3 units

 Then,  DB = 8 units -  2 units  = 6 units,

              EC = 12 units - 3 units   =  9 units

⇒\frac{AD}{DB}  =  \frac{2}{6} =  \frac{1}{3} ,  \\ \frac{AE}{EC}  =    \frac{3}{9}   =  \frac1}{3}

⇒\frac{AD}{DB}  =  \frac{AE}{EC}  =\frac{1}{3}

Hence,   ΔABC and ΔADE are similar.

4 0
3 years ago
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