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PilotLPTM [1.2K]
2 years ago
13

1/20 written as a decimal

Mathematics
2 answers:
Margarita [4]2 years ago
7 0
First multiply the top and bottom of the fraction by 5 so it is out of 100.
Now that you have 5/100 you can easily change the numerator into a decimal
Answer .5
egoroff_w [7]2 years ago
4 0
Divide 1 by 20.
1÷20= 0.05
so 1/20 written as a decimal is 0.05
You might be interested in
How do you solve twelve less than the quotient of a number and 7 is -2
Drupady [299]

Remark

One of the things you need to do is learn to read phrase by phrase.

What is the quotient of a number and 7? That meas you have a number, x, and it is divided by 7. What you do that the answer you get is the quotient.

x/7 is what you know so for. Now the first part says you take 12 away from that.

x/7 - 12 is what you have after doing that.

The result you get is - 2

x/7 - 12 = - 2 Add 12 to both sides

x/7 - 12 + 12 = - 2 + 12

x/7 = 10 Now multiply by 7

x = 10 *7

x = 70 <<< Answer the number is 70


6 0
3 years ago
A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

6 0
2 years ago
What is 2(-9x-4y-7) simplified
Setler79 [48]
-18x-8y-14 because you need to distribute the digits
4 0
3 years ago
Which of the following illustrates how to find the difference of 4h^5k and -7hk^5
MrRa [10]

Answer:

Not possible

Step-by-step explanation:

Which of the following illustrates how to find the difference of 4h^5k and -7hk^5

Takig the difference

4h^5k - (-7hk^5)

= 4h^5k +7hk^5

Collect the like terms

= hk(4h^4+7k^5)

Hence the difference is not possible

7 0
3 years ago
Help please..............
Aleonysh [2.5K]

Answer:

Basically ur wrong

Step-by-step explanation:

6 0
3 years ago
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