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klio [65]
3 years ago
5

Find the value of the variable such that: the value of 5−a is 20 greater than the value of 6a−1

Mathematics
1 answer:
vovangra [49]3 years ago
4 0

Answer:

-2

Step-by-step explanation:

(5 - a) = 20 + (6a -1) . . . . . 5-a is 20 greater than 6a-1

5 = 7a +19 . . . . . . . . . . . . . add a, collect terms

-14 = 7a . . . . . . . . . . . . . . . subtract 19

-2 = a . . . . . . . . . . . . . . . . divide by 7

The value of the variable is -2.

_____

<u>Check</u>

5 - (-2) = 7

6(-2) -1 = -13

7 is 20 greater than -13, so the answer checks OK.

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B is the midpoint of AC and E' is the midpoint of BD. If A(-9,-4), C(-1, 6), and E(-4,-3), find the coordinates of D.
Ipatiy [6.2K]
The coordinates for D are (-4, -7)

First we must locate point B as it is vital to finding the midpoint of BD. To do this, we take the average of the endpoints AC since B is its midpoint. 

x values = -9 + 1 = -8
Then divide by 2 for the average -8/2 = -4

y values = -4 + 6 = 2
Then divide by 2 for the average 2/2 = 1

Therefore B must be (-4, 1)

Now we know the values of E must be the average of B and D. So we can write equations for each coordinate since we know they are averages. 

x - values = (Bx + Dx)/2 = Ex
(-4 + Dx)/2 = -4 ---> multiply both sides by 2
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y - values = (By + Dy)/2 = Ey
(1 + Dy)/2 = -3 ---> multiply both sides by 2
1 + Dy = -6 ---> subtract 1 from both side
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So the coordinates for D must be (-4, -7)
5 0
3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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