What number must you add to complete the square x^2+20x=33

Mathematics

1 answer:

Natali [406]3 years ago

3 0

X²+20x-33=0
x²+2(10) (x) +10²-10 ²-33=0
(x+10) ²=133
x+10=±√133

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Simone can archange $100 for 300 Swiss francs. At that rate, how many dollars would a 330-franc Swiss

makvit [3.9K]

Answer:

450

Step-by-step explanation:

4 0

3 years ago

What is the solution for the system of equations? Use the substitution method to solve. 2x+y=20

slava [35]

2x + y = 20

-5y = -6x + 12

To use the substitution method, first isolate one of the variables in one of the equations.

Isolate the "y" in the first equation (because it is the easiest to isolate), and substitute it into the second equation:

2x + y = 20 Subtract 2x on both sides

y = 20 - 2x

-5y = -6x + 12 (since y = 20 - 2x, you can substitute 20 - 2x into y)

-5(20 - 2x) = -6x + 12 Multiply -5 into (20 - 2x)

-100 + 10x = -6x +12 Add 100 on both sides

10x = -6x + 112 Add 6x on both sides

16x = 112 Divide 16 on both sides

x = 7

Now that you have found x, you can substitute 7 into x for one of the original equations:

2x + y = 20

2(7) + y = 20

14 + y = 20 Subtract 14 on both sides

y = 6

-5y = -6x + 12

-5y = -6(7) + 12

-5y = -42 + 12

-5y = -30 Divide -5 on both sides

y = 6

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3 years ago

H e l p p l e a s e

BigorU [14]

Answer:

17.) 12

18.) 1/15

Step-by-step explanation:

2 ÷ $\frac{1}{6}$

This problem is asking how many $\frac{1}{6}$ 's can go into 2 blocks. If you divide one box into 6 parts, each tiny box will be $\frac{1}{6}$ of the whole. Divide the other box into 6 parts as well, and you will get 12 of these $\frac{1}{6}$ parts. Check your answer by multiplying 12 by $\frac{1}{6}$ . The answer is $\frac{12}{6}$ which is also equal to 2.

$\frac{1}{3}$ ÷ 5

For this one, think of it as we have one big box divided into thirds. We want to divide each $\frac{1}{3}$ portion by 5. So you should have 5 tiny boxes in each $\frac{1}{3}$ which gives you a total of 15 boxes. But if we look at it as one big box divided into 15 parts, we know that each of those is $\frac{1}{15}$ . Check your answer by multiplying $\frac{1}{15}$ by 5 and you get $\frac{5}{15}$ which is equal to $\frac{1}{3}$ .