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4 years ago

Which of the following is not an integer?

Mathematics

1 answer:

In-s [12.5K]4 years ago

5 0

Answer:

$-\frac{54}{7}$

Step-by-step explanation:

The first number is $\sqrt{\frac{64}{4} }$

We simplify to get: $\sqrt{\frac{64}{4} }=\sqrt{16}=4$

The second number is $-\frac{54}{7}$ .

This number can be rewritten as $7 \frac{5}{7}=7.714285714287$

This is not an integer

The third number is $(\frac{-25}{5})^2$

We simplify to get: $(\frac{-25}{5})^2=(-5)^2=25$

This is also an integer.

The correct answer is $-\frac{54}{7}$ .

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Suppose your statistics instructor gave six examinations during the semester. You received the following grades (percent correct

andriy [413]

Answer:

a. 15

Sr.no Samples Sample mean

1 (79,64) 71.5

2 (79,84) 81.5

3 (79,82) 80.5

4 (79,92) 85.5

5 (79,77) 78

6 (64,84) 74

7 (64,82) 73

8 (64,92) 78

9 (64,77) 70.5

10 (84,82) 83

11 (84,92) 88

12 (84,77) 80.5

13 (82,92) 87

14 (82,77) 79.5

15 (92,77) 84.5

mean of sample mean=population mean=79.67

Step-by-step explanation:

The different samples of two test grade are nCr, where n=6 and r=2.

nCr=6C2=6!/2!(6-2)!=6*5*4!/2!4!=30/2=15.

Thus, there are 15 different samples of two test grade.

All possible samples are listed below:

Sr.no Samples

1 (79,64)

2 (79,84)

3 (79,82)

4 (79,92)

5 (79,77)

6 (64,84)

7 (64,82)

8 (64,92)

9 (64,77)

10 (84,82)

11 (84,92)

12 (84,77)

13 (82,92)

14 (82,77)

15 (92,77)

The sample means for each sample can be calculated as

Sr.no Samples Sample mean

1 (79,64) (79+64)/2=71.5

2 (79,84) (79+84)/2=81.5

3 (79,82) (79+82)/2=80.5

4 (79,92) (79+92)/2=85.5

5 (79,77) (79+77)/2=78

6 (64,84) (64+84)/2=74

7 (64,82) (64+82)/2=73

8 (64,92) (64+92)/2=78

9 (64,77) (64+77)/2=70.5

10 (84,82) (84+82)/2=83

11 (84,92) (84+92)/2=88

12 (84,77) (84+77)/2=80.5

13 (82,92) (82+92)/2=87

14 (82,77) (82+77)/2=79.5

15 (92,77) (92+77)/2=84.5

The sample means of sample mean μxbar will calculated by taking average of sample means

μxbar=(71.5+ 81.5+ 80.5+ 85.5+ 78+ 74+ 73+ 78+ 70.5+ 83+ 88+ 80.5+ 87+ 79.5+ 84.5)/15

μxbar=1195/15=79.67

Population mean=μ=(79+64+84+82+92+77)/6

μ=478/6=79.67

Sample means of sample mean μxbar=Population mean μ.

5 0

4 years ago

Write the equation of the line passing through the points (-1, 2) and (3.4)

Bond [772]

Answer:

$\boxed{y = 0,5x + 2,5}$

Step-by-step explanation:

Equation of a straight line: y = kx + b

Points: (-1,2) and (3,4)

Сompose the system of equations:

$\displaystyle \left \{ {{2=-k + b} \atop {4=3k + b}} \right$ $\displaystyle \left \{ {{b= k + 2} \atop {b=4 - 3k}} \right \Longrightarrow 2 + k = 4 - 3k$

$2 + k = 4 - 3k$

$4k = 2|:4$

$k = 0,5$

$b = k + 2 = 0,5 + 2 = 2,5$

$y = 0,5x + 2,5$

6 0

3 years ago

A. Find x<br>b. Is the triangle equilateral isosceles or scalene?<br><br>please explain

spayn [35]

180 = 24 x
7.5 = x

angle P = 85
angle Q = 45
angle R = 50

No this triangle is scalene because the sides nor the angles are congruent.

3 0

2 years ago

A jeweler wants to make 8 grams of a mixture that is 75% gold. She has an alloy that is 90% gold and an alloy that is 50% gold.

Alisiya [41]

Answer: The dealer should use 5 grams of alloy that is 90% gold and a3 grams of alloy that is 50% gold.

Step-by-step explanation:

Let x be the weight of alloy having 90% gold and y be the weight of alloy having 50% gold .

Given : A jeweler wants to make 8 grams of a mixture that is 75% gold. She has an alloy that is 90% gold and an alloy that is 50% gold.

According to the above statement , we have the following system of equations :-

$\text{Total weight of mixture }: x+y=8-----------------(1)\\\\\text{proportion of gold in mixture}: \dfrac{0.90x+0.50y}{8}=0.75\\\\=0.90x+0.50y=6--------------------(2)$