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Anarel [89]
3 years ago
9

Witch statement best describes how to determine whether f(x) =x^3+5x+1 is an even function?

Mathematics
1 answer:
34kurt3 years ago
3 0
A.Determine whether –(x3 + 5x + 1) is equivalent to x3 + 5x + 1. b.Determine whether (–x)3 + 5(–x) + 1 is equivalent to x3 + 5x + 1.
c. Determine whether –x3 + 5x + 1 is equivalent to –(x3 + 5x + 1).
d. Determine whether (–x)3 + 5(–x) + 1 is equivalent to –(x3 + 5x + 1)

A function is even if f(x) = f(-x) for all x.

f(-x) = -x³ + 5(-x) + 1
f(-x) = -x³ - 5x + 1

b.Determine whether (–x)3 + 5(–x) + 1 is equivalent to x3 + 5x + 1. 
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Information regarding various dogs' masses is displayed in the table.

(a) 4 bare minimum number of dogs that could weigh more than 27 kg.

(b) 17 dogs, in total, may weigh more than 27 kg.

Given that,

Information regarding various dogs' masses is displayed in the table.

(a)Calculate the bare minimum number of dogs that could weigh more than 27 kg.

(b)Calculate how many dogs, in total, may weigh more than 27 kg.

(a) 4 bare minimum of dogs that could weigh more than 27 kg.

Because the minimum number so lets assume that all dogs in 20≤x<30 are less then 27.

Therefore, 4 bare minimum of dogs that could weigh more than 27 kg.

(b) 17 dogs, in total, may weigh more than 27 kg.

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4+13=17

Therefore,17 dogs, in total, may weigh more than 27 kg.

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