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3 years ago

2 to the 3rd power divided by 2 to the 6th power

Mathematics

1 answer:

marissa [1.9K]3 years ago

5 0

1/8 is the answer you’re welcome

You might be interested in

Understanding the Pythagorean Theorem – Finding an Unknown Hypotenuse (find the distance of the mechanical webbing needed by Spi

barxatty [35]

Answer:

100√65 yds

Step-by-step explanation:

The Pythagorean Theorem is a^2+b^2=c^2. In this case a=700, b=400, and c is the unknown.

700^2+400^2=c^2
490000+160000=c^2
650000=c^2
c=√650000

√650000=√(100^2•65)=100√65

7 0

3 years ago

Please help me with this I don’t know how to do it

Anna35 [415]

Answer:

Step-by-step explanation:

4 0

3 years ago

PLEASE HELP THIS SHOULD BE MY LAST ONE

n200080 [17]

Answer:

g(-4) = -4

g(-2) = 1

g(1) = -4

Step-by-step explanation:

The value of the given function is -4 for all values of x other than -2 and 1 if x=-2

So,

For x=-4 the value of function will be -4.

g(-4) = -4

For x=-2

The value of function is -2.

g(-2) = 1

And for x=1, the value will be -4.

g(1) = -4 ..

3 0

4 years ago

Suppose $4000 is invested at 3% interest compounded monthy. How much money will there be in the bank at the end of 15 years?

Brilliant_brown [7]

Since the interest rises 3% monthly, you have to keep taking your number and multiplying it by 3% each month and when you keep doing this, you end up with $6,269.73.

8 0

3 years ago

An environmentalist wants to find out the fraction of oil tankers that have spills each month. Suppose a sample of 836 tankers i

Alexxandr [17]

Answer:

The 99% confidence interval for the population proportion of oil tankers that have spills each month.

(0.6489 , 0.7311)

Step-by-step explanation:

Step(i):-

Given sample size 'n' = 836

Suppose a sample of 836 tankers is drawn. Of these ships, 577 did not have spills.

sample proportion

$p^{-} = \frac{x}{n} = \frac{577}{836} = 0.690$

The 99% confidence interval for the population proportion is determined by

$(p^{-} - Z_{0.01} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.01} \sqrt{\frac{p(1-p)}{n} })$

Step(ii):-

The Z- value = 2.576

$(0.690 - 2.576 \sqrt{\frac{0.690(1-0.690)}{836} } , 0.690 + 2.576 \sqrt{\frac{0.690(1-0.690)}{836} })$

On calculation , we get

(0.690 - 0.0411 , 0.690 + 0.0411)

(0.6489 , 0.7311)

Final answer:-

The 99% confidence interval for the population proportion of oil tankers that have spills each month.

(0.6489 , 0.7311)

8 0

4 years ago