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aksik [14]
3 years ago
5

Find the difference. 3 1/4 - 1/6 = Enter your answer as a mixed number.

Mathematics
2 answers:
romanna [79]3 years ago
6 0
18 1/2, hope this helps :)
maria [59]3 years ago
3 0

Answer:18 1/2

Step-by-step explanation:

3 1/4 - 1/6

(4x3+1)/4 - 1/6

13/4 - 1/6

(3x13-2x1)/12

(39-2)/12

37/2=18 1/2

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Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From
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Answer:

The 95% CI for the difference of means is:

-155.45 \leq \mu_1-\mu_2 \leq -44.55

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."</em>

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size:  4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

M_d=M_1-M_2=200-300=-100

The standard deviation can be estimated as:

\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45

The degrees of freedom are:

df=n_1+n_2-2=10+4-2=12

The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55

8 0
3 years ago
Someone please hurry and answer i will mark brainelist!!!!! or how ever you spell it
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What is the question?

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Step-by-step explanation:

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Frankly, substitution is almost always a better method. Graphing is a very precise and time consuming process where you have to calculate several..

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