Please help me!!!!<br> 50 points for you, if you help me!!!!!!!!

BRAINLYEST!! What can you conclude from the scatterplot shown below?

VladimirAG [237]

Answer:

first one

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

1. 9c-3c=48A) c=9B) c=3C) c=4D) C=8

Alona [7]

$9c\text{ - 3c = 48}$

To solve this equation, we need to subtract both, 9c - 3c:

$9c\text{ - 3c = 6c = 48}$

Dividing by 6 at both sides of the equation

$\frac{6c}{c}\text{ = }\frac{48}{6}$

Then

$c\text{ = 8}$

Then the answer C = 8. (Option D)

3 0

1 year ago

Lin's sister has a checking account. If the account balance ever falls below zero, the bank charges her a fee of $5.95 per day.

VladimirAG [237]

Answer: No, the bank will not keep charging her the $5.95 after the deposit is made.

Step-by-step explanation:

Today, Lin's sister's balance is -$2.67

She gets charged $5.95 per day.

There are 14 days until she can charge some money in the bank account, so the bank will charge $5.92 14 times

So her balance after 14 days will be:

Balance = -$2.67 - $5.95*14 = -$85.97

When she charges the $430 in the account, her balance will be:

Balance = -$85.97 + $430 = $344.03

So now she has a positive balance, which means that the bank does not charge her anymore.

5 0

3 years ago

Find two consecutive even integers such that the square of the second, decreased by twice the first is 52

Fiesta28 [93]

Let the first integer be $x$ . So, the next even number is $x+2$

Let's translate the formula: the square of the second is $(x+2)^2$ , twice the first is $2x$ . So, the equation is

$(x+2)^2 - 2x = 52$

Expand the square to get

$x^2+4x+4-2x = 52 \iff x^2+2x+4 = 52 \iff x^2+2x - 48 = 0$

The solutions to this equations are

$x = -8,\quad x = 6$

So, the possible consecutive even numbers are

$-8\text{ and } -6\quad\text{or}\quad 6\text{ and } 8$

8 0

3 years ago

Which the is the correct answer?

agasfer [191]

To solve this problem, we need to use combination which is statistical tool to determine the number of ways an event may occur. The combination to select a 5 a side team from 12 students is 792.

<h3>Combination</h3>

This a mathematical technique that is used to determine the number of possible arrangements in a collection of items where the way they're arranged does not matter.

Data;

Number of Students = 12
Team = 5

The combination for this would be

$C = ^1^2C_5 = 792$

The combination to select a 5 a side team from 12 students is 792.

Learn more on combination here;

brainly.com/question/251701

#SPJ1

4 0

2 years ago

Please help me!!!! 50 points for you, if you help me!!!!!!!!