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3 years ago

Given mq=tn, mq|| TN. prove Mn=tq

Mathematics

1 answer:

Nonamiya [84]3 years ago

5 0

You can't prove except if you have another informations<span />

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TConsider △RST and △RYX.

Kryger [21]

For similar triangles ΔRST and ΔRYX proportion RY/RS = RX/RT = XY/TS is true.

Given that, for ΔRST, line XY is drawn parallel to side ST within ΔRST to form ΔRYX.

Considering ΔRST and ΔRYX.

<h3>What is the relation between sides of similar triangles?</h3>

The corresponding sides of similar triangles are proportional.

We get ∠RXY=∠RST (Corresponding angles, since XY║ST)

∠RYX=∠RTS (Corresponding angles, since XY║ST)

From AA similarity criteria ΔRST is similar to ΔRYX.

Now, RY/RS = RX/RT = XY/TS.

Therefore, for similar triangles ΔRST and ΔRYX proportion RY/RS = RX/RT = XY/TS is true.

To learn more about similar triangles visit:

brainly.com/question/25882965.

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4 0

2 years ago

Can someone please help me figure out if there similar and then the rest

Oksana_A [137]

The figures have corresponding sides that are proportional, therefore, they are similar figures.

<h3>What are Similar Figures?</h3>

When two figures are similar to each other, the corresponding sides are proportional to each other.

The two figures given have two opposite sides that are parallel and congruent to each other. Therefore:

DA/VS = 21/7 = 3

AB/ST = 15/5 = 3

Thus, we can conclude that since their corresponding sides are proportional, therefore, they are similar to each other.

Learn more about similar figures on:

brainly.com/question/4381215

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8 0

2 years ago

A map shows the distance between the corner of cactus road and 1st street and the corner of 1 St Street and Merle road as 3 inch

melamori03 [73]

11.1 miles

1in / 3.7 m = 3 in / 11.1 m

8 0

3 years ago

Read 2 more answers

A 4-centimeter rod is attached at one end A to a point on a wheel of radius 2 cm. The other end B is free to move back and forth

zloy xaker [14]

Answer:

Step-by-step explanation:

The triangle that was formed has radius 2:

hypotenuse = 2

adjacent = x = 2*cosθ

opposite = y = 2*sinθ

from the first picture on the left, we see that the rod has length of 4.

We then use pythagoras theorem with respect to the triangle formed with the rod, i.e, the opposite leg, and the length of the remaining side (say, L), we have:

2²sin²θ +L² = 4²

On rearranging and making L subject of formula, we have

L = √(16 - 4sin²θ)

L = 2√(4 - sin²θ)

Also, the distance of point B is from the center of the circle, and it is:

2cosθ + 2√(4 - sin²θ)

We know that

3.5 revolutions per second means 3.5(2π) per second.

7π radians per second

So we try to write the angle formed as:

θ = 7π*t

where t is the time in seconds.

(a)

2cos(7πt) + 2√(4 - sin²(7πt))

at t = 1/21 we substitute for t, and then

2cos(π/3) + 2√(4 - sin²(π/3))

= 1 + √13 or approximately 4.6

(b)

(c)

B = 2cos(7πt) + 2√(4 - sin²(7πt))

dB/dt = - 14πsin(7πt) - { 14π*cos(7πt)sin(7πt)/√(4 - sin²(7πt)) }

4 0

3 years ago

Which of the functions below have period pie check all that apply

Shtirlitz [24]

There is no photo attached.

7 0

3 years ago