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MakcuM [25]
4 years ago
11

Simplify the equation 3c+9-2c-6

Mathematics
1 answer:
Liula [17]4 years ago
7 0

Answer:

c+3..................

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The slope of a line is -1/5 and the y-intercept is 5
fgiga [73]
The equation of a line is:
y = -x/5 + 5

or

x + 5y = 25
4 0
3 years ago
Read 2 more answers
The population for Gulch Dry has been declining according to the function P(t)= 8000. 2^-t/29 where t is the number of years sin
Iteru [2.4K]
A)

\bf 1990-1910=80\leftarrow t
\\\\\\
P(t)=8000(2)^{-\frac{t}{29}}\implies P(80)=8000(2)^{-\frac{80}{29}}
\\\\\\
P(80)=8000\cdot \cfrac{1}{2^{\frac{80}{29}}}\implies P(80)=\cfrac{8000}{\sqrt[29]{2^{80}}}

and surely you know how much  that is.

b)

\bf P(t)=125\\\\\\  125=8000(2)^{-\frac{t}{29}}\implies \cfrac{125}{8000}=2^{-\frac{t}{29}}\implies \cfrac{1}{64}=2^{-\frac{t}{29}}
\\\\\\
\textit{now we take log to both sides}
\\\\\\
log\left( \frac{1}{64} \right)=log\left( 2^{-\frac{t}{29}} \right)\implies log\left( \frac{1}{64} \right)=-\frac{t}{29}log\left( 2 \right)
\\\\\\
log\left( \cfrac{1}{64} \right)=-\cfrac{tlog(2)}{29}\implies \cfrac{-29log\left( \frac{1}{64} \right)}{log(2)}=t\implies 174=t

since in 1910 t = 0, 174 years later from 1910, is 2084, so in 2084 they'll be 125 exactly, so the next year, 2085, will then be the first year they'd fall under that.
6 0
4 years ago
The half-life of the radioactive isotope gallium-70 is 20 minutes. The initial amount of gallium-70 is 25 milligrams. When will
stiv31 [10]

Answer:

Whether or not a given isotope is radioactive is a characteristic of that particular isotope. Some isotopes are stable indefinitely, while others are radioactive and decay through a characteristic form of emission. As time passes, less and less of the radioactive isotope will be present, and the level of radioactivity decreases. An interesting and useful aspect of radioactive decay is half-life, which is the amount of time it takes for one-half of a radioactive isotope to decay. The half-life of a specific radioactive isotope is constant; it is unaffected by coTnditions and is independent of the initial amount of that isotope.

6 0
3 years ago
Read 2 more answers
Tamara earned 15% more each week in September than in July. She earned 10% less each week in July than in August. If she earned
Zanzabum

Answer: 34.10

Find 15% of 207 then ten percent of that and add it to that theres ur answer.

4 0
3 years ago
If n is a positive integer, then lim (n-->infinity) (1/n) [1/(1+(1/n)) + 1/(1+(2/n))+...+1/(1+(n/n)] is?
Anton [14]
The correct answer to this question is <span>d.) integral from 1 to 2 of (2/(x+1))
</span>To solve this:

Since Δx = 1/n. 
lim (n→∞) Δx [1/(1+Δx) + 1/(1+2Δx)+ ... + 1/(1+nΔx)] 
= lim (n→∞) Σ(k = 1 to n) [1/(1 + kΔx)] Δx. 

x <---> a + kΔx 

a = 0, then b = 1, so that Δx = (b - a)/n = 1/n

Since (1 + kΔx) combination, a = 1 so that b = 2. 
Then, f(1 + kΔx) <-----> f(x) ==> f(x) = 1/x. 

This sum represents the integral 
∫(x = 1 to 2) (1/x) dx, so the correct answer is <span>d.) integral from 1 to 2 of (2/(x+1))

Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help. 
</span>
3 0
3 years ago
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