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3 years ago

Find the mode of the following data set.

Mathematics

2 answers:

ivolga24 [154]3 years ago

8 0

The mode is the number that shows up the most.

In the dataset, note that the stem should be in the tens place, and the different number of leaves are in the ones place.

62 shows up one more time than all the other numbers, and so 62 is your answer.

Hope this helps

8090 [49]3 years ago

7 0

Let's look at the options we're given. We need an answer that has two digits, not just one. So that would automatically kick out the first and second answer and leave you with the third one.
But, if you didn't have the options and had to figure it out base on the information, you can tell that there are two 2's with 6, meaning there are two 62's. There are no other duplicates, meaning 62 shows up the most than any of the other numbers.
The mode is 62.

Tell me if this helps!!

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Write an inequality and solve each problem.

baherus [9]

The unknown number equals x. (you can use any other letter)
the unknown number is being subtracted by 3.
x-3.
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x-3<2
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3 years ago

Two of the statements are true; one is a lie.

olya-2409 [2.1K]

Answer:

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3 years ago

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Natalie picked 135 berries in 15 minutes. If she continues picking at that rate, how many total minutes will it take her to pick

Alex777 [14]

Lets focus on what we know first. Natalie can pick 135 Berries in 15 minutes. Lets find out how many berries she can pick per minute.
In order to do so, We have to divide 135 by 15.

135/15=9
This means that Natalie can pick 9 berries per minute. Given that we want her to pick 486, we will need to divide that number by 9 berries to find out how many minutes it will take to get her to that number of berries.

486/9=54

This means that it will take Natalie 54 minutes in order to pick 486 berries.

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3 years ago

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Zielflug [23.3K]

Answer:

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3 years ago

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Assume we need to estimate the mean of a normally-distributed population with great accuracy. Specifically, for significance lev

bulgar [2K]

Answer:

$n = 2662.56\sigma^2$

Step-by-step explanation:

We are given the following in the question:

Significance level = 0.01

Width of interval = 0.1

Population variance = $\sigma^2$

We have to find the sample size so that the width of the confidence interval is no larger than 0.1

$z_{critical}\text{ at}~\alpha_{0.01} = \pm 2.58$

Formula for sample size:

$n = \displaystyle\frac{z^2\sigma^2}{E^2}$

where E is the margin of error. Since the confidence interval width is 0.1,

$E = 0.05$

Putting these values in the equation:

$n = \displaystyle\frac{(2.58)^2\sigma^2}{(0.05)^2} = 2662.56\sigma^2$

So, the above expression helps us to calculate the sample size so that the width of the confidence interval is no larger than 0.1 for different sample variances.

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3 years ago