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alina1380 [7]
3 years ago
15

What is the following sum 2{^3 square root 16x^3y}+4{^3 square root 54x^6y^5}?

Mathematics
2 answers:
Kay [80]3 years ago
8 0
2\sqrt[3]{16x^{3}y}+4\sqrt[3]{54x^{6}y^5}}=2\sqrt[3]{(2x)^{3}\cdot 2y}+4\sqrt[3]{(3x^{2}y)^{3}\cdot 2y^{2}}\\\\=4x\sqrt[3]{2y}+12x^{2}\sqrt[3]{2y^{2}}
Flauer [41]3 years ago
7 0

Answer:

4x\sqrt[3]{2y} +12x^2y\sqrt[3]{2y^2}

Step-by-step explanation:

Given expression 3\sqrt[3]{16x^3y} + 4\sqrt[3]{54x^6y^5}.

Let us simplify each of the radical separately first.

3\sqrt[3]{16x^3y}=3\sqrt[3]{2\times 8 \times x^3\times y} =2\sqrt[3]{2} \times \sqrt[3]{8} \times \sqrt[3]{x^3} \times \sqrt[3]{y}

=2\sqrt[3]{2} \times 2\times x\times \sqrt[3]{y}

= 2\times 2\times x\sqrt[3]{2y}

= 4x\sqrt[3]{2y}

4\sqrt[3]{54x^6y^5}=4\sqrt[3]{2\times 27 \times x^3\times x^3 \times y^3\times y^2} =4\sqrt[3]{2} \times \sqrt[3]{27} \times \sqrt[3]{x^3} \times \sqrt[3]{x^3} \times \sqrt[3]{y^3}\times\sqrt[3]{y^2}

=4\sqrt[3]{2} \times 3 \times x\times x \times y \times \sqrt[3]{y^2}

=12x^2y\sqrt[3]{2y^2}

Therefore,

3\sqrt[3]{16x^3y} + 4\sqrt[3]{54x^6y^5} =4x\sqrt[3]{2y} +12x^2y\sqrt[3]{2y^2}


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timama [110]

Step-by-step explanation:

5w < 15 \\  \frac{5w}{5}  <  \frac{15}{5}  \\ w < 3

4 0
4 years ago
Need Help
grigory [225]
<h3>Answer:  Approximately 191 bees</h3>

================================================

Work Shown:

One way to express exponential form is to use

y = a*b^x

where 'a' is the initial value and 'b' is linked to the growth rate.

Since we're told 34 bees are there initially, we know a = 34.

Then after 4 days, we have 48 bees. So we can say,

y = a*b^x

y = 34*b^x

48 = 34*b^4

48/34 = b^4

24/17 = b^4

b^4 = 24/17

b = (24/17)^(1/4)

b = 1.090035

Which is approximate.

The function updates to

y = a*b^x

y = 34*(1.090035)^x

------------------------

As a way to check to see if we have the right function, plug in x = 0 and we find:

y = 34*(1.090035)^x

y = 34*(1.090035)^0

y = 34*(1)

y = 34

So there are 34 bees on day 0, ie the starting day.

Plug in x = 4

y = 34*(1.090035)^x

y = 34*(1.090035)^4

y = 34*1.4117629

y = 47.9999386

Due to rounding error we don't land on 48 exactly, but we can round to this value.

We see that after 4 days, there are 48 bees.

So we confirmed the correct exponential function.

------------------------

At this point we can find out how many bees there are expected to be after 20 days.

Plug in x = 20 to get

y = 34*(1.090035)^x

y = 34*(1.090035)^20

y = 190.672374978452

Round to the nearest whole number to get 191.

There are expected to be roughly 191 bees on day 20.

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blondinia [14]

Answer:

1496.52 Pa, 14.76 atm

Step-by-step explanation:

This question can be solved using ideal gas law

according to which

pv = nrt

where p is the pressure of gas

v is volume of gas

n is amount gas in moles

R is ideal gas constant whose value is 8.314 J/mol

T is absolute temperature of gas on Kelvin scale

______________________________

given

v = 5 liter

n = 3

T = 300 kelvin

R = 8.314 J/mol

Let the pressure be p

Substituting the above value in ideal gas law equation we have

p*5 = 3*8.314*300

p = 7482.6/5 = 1496.52 Pa

This pressure is in pascal while option is in atm

we know 1 Pascal is equal to 0.0000098692 atm

we know that 1 Atm = 101325 Pa

thus, 1496.52 is equal to  0.0000098692*1496.52 atm

1496.52 is equal to 14.76 atm

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A truck makes a trip of 14 hours, what was the speed if it traveled 2438 km?
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Answer:

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Step-by-step explanation:

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