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alina1380 [7]
3 years ago
15

What is the following sum 2{^3 square root 16x^3y}+4{^3 square root 54x^6y^5}?

Mathematics
2 answers:
Kay [80]3 years ago
8 0
2\sqrt[3]{16x^{3}y}+4\sqrt[3]{54x^{6}y^5}}=2\sqrt[3]{(2x)^{3}\cdot 2y}+4\sqrt[3]{(3x^{2}y)^{3}\cdot 2y^{2}}\\\\=4x\sqrt[3]{2y}+12x^{2}\sqrt[3]{2y^{2}}
Flauer [41]3 years ago
7 0

Answer:

4x\sqrt[3]{2y} +12x^2y\sqrt[3]{2y^2}

Step-by-step explanation:

Given expression 3\sqrt[3]{16x^3y} + 4\sqrt[3]{54x^6y^5}.

Let us simplify each of the radical separately first.

3\sqrt[3]{16x^3y}=3\sqrt[3]{2\times 8 \times x^3\times y} =2\sqrt[3]{2} \times \sqrt[3]{8} \times \sqrt[3]{x^3} \times \sqrt[3]{y}

=2\sqrt[3]{2} \times 2\times x\times \sqrt[3]{y}

= 2\times 2\times x\sqrt[3]{2y}

= 4x\sqrt[3]{2y}

4\sqrt[3]{54x^6y^5}=4\sqrt[3]{2\times 27 \times x^3\times x^3 \times y^3\times y^2} =4\sqrt[3]{2} \times \sqrt[3]{27} \times \sqrt[3]{x^3} \times \sqrt[3]{x^3} \times \sqrt[3]{y^3}\times\sqrt[3]{y^2}

=4\sqrt[3]{2} \times 3 \times x\times x \times y \times \sqrt[3]{y^2}

=12x^2y\sqrt[3]{2y^2}

Therefore,

3\sqrt[3]{16x^3y} + 4\sqrt[3]{54x^6y^5} =4x\sqrt[3]{2y} +12x^2y\sqrt[3]{2y^2}


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