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attashe74 [19]
4 years ago
5

If you bought a stock last year for a price of $73, and it has risen 7.1% since then, how much is the stock worth now, to the ne

arest cent?
Mathematics
2 answers:
mixas84 [53]4 years ago
8 0

Answer:

$78.11

Step-by-step explanation:

MA_775_DIABLO [31]4 years ago
7 0

Answer:

78.18

Step-by-step explanation:

73 times 1.071=78.183

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Vaselesa [24]

HI 1 + 1 IS EQUAL TO 2 SO2 + 2 IS EQUAL TO 4 SO 4 + 4 IS EQUAL TO 8

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2 years ago
Twice a number decreased by the cube of the same number
Aliun [14]
2(n)-n^2

Reorder in standard form: ax^2 + bx + c

-n^2 + 2n + 0
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3 years ago
Solve it please with explanation Marty simplified the expression 2(x - 2) - 2(3) as 2x - 8. Is he correct? Explain why or why no
Kamila [148]

Answer: Marty is not correct

Step-by-step explanation:

2(x-2)-2(3) use distributive property

2x-4-6

2x-10

Marty is not correct

3 0
2 years ago
Read 2 more answers
If f(x)=ln x and g(x)=e^x+1 find f(g(2))-g(f(e)) please help!!
Readme [11.4K]

Answer:

<h3>ln (e^2 + 1) - (e+ 1)</h3>

Step-by-step explanation:

Given f(x) = ln and g(x) = e^x + 1 to get  f(g(2))-g(f(e)), we need to first find the composite function f(g(x)) and g(f(x)).

For f(g(x));

f(g(x)) = f(e^x + 1)

substitute x for e^x + 1 in f(x)

f(g(x)) = ln (e^x + 1)

f(g(2)) = ln (e^2 + 1)

For g(f(x));

g(f(x)) = g(ln x)

substitute x for ln x in g(x)

g(f(x)) =  e^lnx + 1

g(f(x)) = x+1

g(f(e)) = e+1

f(g(2))-g(f(e)) = ln (e^2 + 1) - (e+ 1)

5 0
3 years ago
The annual precipitation amounts in a certain mountain range are normally distributed with a mean of 104 inches, and a standard
dsp73

Answer:

91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 104, \sigma = 14, n = 49, s = \frac{14}{\sqrt{49}} = 2

What is the probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

This is the pvalue of Z when X = 106.8. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{106.8 - 104}{2}

Z = 1.4

Z = 1.4 has a pvalue of 0.9192

0.9192 = 91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

8 0
4 years ago
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