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zheka24 [161]
4 years ago
12

Find the unknown lengths of the sides of each triangle.

Mathematics
1 answer:
irga5000 [103]4 years ago
8 0
1. B is 4 and c is 8
2. A and b are 5square root of 2
4. B is 7 and c is 14
5. A and b is 6 square root of 2
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Lina rolled a die. <br><br> What is the probability that she got 3?
erastova [34]
1/6 (if it’s a regular dice you’re talking about.
3 0
3 years ago
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What is 0.4to the power of 6
maxonik [38]

0.4^6 is 0.004096

hope it helps

7 0
3 years ago
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Among 8 PS4s, four are good and four have defects. Unaware of this, a customer buys 5 PS4s.
astraxan [27]

Answer:

(a) The probability of exactly 2 defective PS4s among them is 0.3125.

(b) The probability that exactly ​ 2 are defective given that  ​at least ​ 2 purchased PS4s are defective is 0.3846.

Step-by-step explanation:

Let <em>X</em> = number of defective PS4s.

It is provided that 4 PS4s of 8 are defective.

The probability of selecting a defective PS4 is:

P(X)=p=\frac{4}{8}=0.50

A customer bought <em>n</em> = 5 PS4s.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.50.

The probability function of a Binomial distribution is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0, 1, 2, 3...

(a)

Compute the probability of exactly 2 defective PS4s among them as follows:

P(X=2)={5\choose 2}(0.50)^{2}(1-0.50)^{5-2}=10\times0.25\times0.125=0.3125

Thus, the probability of exactly 2 defective PS4s among them is 0.3125.

(b)

Compute the probability that exactly ​ 2 are defective given that  ​at least ​ 2 purchased PS4s are defective as follows:

P(X=2|X\geq 2)=\frac{P(X=2\cap X\geq2)}{P(X\geq2)} =\frac{P(X=2)}{P(X\geq 2)}

The value of P (X = 2) is 0.3125.

The value of P (X ≥ 2) is:

P(X\geq 2)=1-P(X

Then the value of P (X = 2 | X ≥ 2) is:

P(X=2|X\geq 2)=\frac{P(X=2)}{P(X\geq 2)}=\frac{0.3125}{0.8125} =0.3846

Thus, the probability that exactly ​ 2 are defective given that  ​at least ​ 2 purchased PS4s are defective is 0.3846.

6 0
4 years ago
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A cone and a cylinder have the same height and their bases are congruent circles
Anettt [7]

Answer:

30cm^3

Step-by-step explanation:

the volume of a cylinder is given by:

v_{cylinder}=\pi r^2 h

and the volume of a cone is given by:

v_{cone}=\frac{\pi r^2 h}{3}

since both have the same height and radius, we can solve each equation for r^2h (because this quantity is the same in both figures) and then match the expressions we find:

from the cylinder's volume formula:

r^2h=\frac{v_{cylinder}}{\pi}

and from the cone's volume formula:

r^2h=\frac{3 v_{cone}}{\pi}

matching the two previous expressions:

\frac{v_{cylinder}}{\pi} =\frac{3v_{cone}}{\pi}

we solve for the volume of a cone v_{cone}:

v_{cone}=\frac{\pi v_{cylinder}}{3\pi} \\\\v_{cone}=\frac{v_{cylinder}}{3}

substituting the value of the cylinder's volume v_{cylinder}=90cm^3

v_{cone}=\frac{90cm^3}{3} \\\\v_{cone}=30cm^3

5 0
3 years ago
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Ordena de menos a mayor las siguientes fracciones:
Ahat [919]
7/12 , 2/3 , 3/4 , 5/6
3 0
3 years ago
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