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Naily [24]
4 years ago
15

Which of the following exhibit only London (dispersion) forces? H2O Cl2

Geography
2 answers:
BARSIC [14]4 years ago
5 0
I would say that the correct answer from the choices given above is the former option. It would be H2O that exhibits london dispersion forces. It <span> is the weakest intermolecular </span>force<span>. The </span>London dispersion force <span>is a temporary attractive </span>force. Hope this answers the question.
Sophie [7]4 years ago
5 0

Answer:

Cl₂ exhibit only London forces

Explanation:

The London dispersion force is an intermolecular force that results when the electrons in two adjacent atoms occupy positions that make the atoms form temporary dipoles. All molecules have london dispersion forces.

Another intermolecular forces are dipole-dipole (Polar molecules with different kind of atoms), hydrogen bonds (Molecules with hydrogen and atoms with high electrongativity) and ion-dipole (Molecules with permanent ions as (alkali metals or halogens and another kind of atom).

Thus:

H₂O exhibit london, hydrogen bond and dipole-dipole forces.

<em>Cl₂ exhibit only London forces.</em>

<em></em>

I hope it helps!

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it is possible for two stars to have different temperatures and different sizes but the same luminosity. explain how.
Darina [25.2K]

Answer:

Two stars (a and b) can have the same luminosity, but different surface area and temperature if the following condition is met:

(T_a^4)(R_a^2) = (T_b^4)(R_b^2)

Explanation:

The luminosity of a star is the total energy that produces in one second. It depends on the size of the star and its surface temperature.

L = σ(T^4)(4πR^2)

L is the luminosity f the star, T is the temperature of the surface of the star and R is its radius.  

Two stars can have the same luminosity if the relation between the radius and the surface temperature is maintained.  

To see this lets suposed you have 2 stars, a and b, and the luminosities of each one of them:

L_a = σ(T_a^4)(4πR_a^2)

L_b = σ(T_b^4)(4πR_b^2)

you can assume that L_a and L_b are equal:

σ(T_a^4)(4πR_a^2) = σ(T_b^4)(4πR_b^2)

Now, you can cancel the constants:

(T_a^4)(R_a^2) = (T_b^4)(R_b^2)

as long as this relation between a and b is true, then the luminosity can be the same.

6 0
3 years ago
Under which economic system are businesses privatly owned with the posssibility of profit?​
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Explanation:

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Hope this helps

Have a great day/night
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