Put the following algebraic expression in standard simplified form. 7-12m-19

Each lap around the track is 1/4 of a mile. How many laps will Quadir need to jog if he wants to jog 3 1/8 miles? Helpppp

weeeeeb [17]

9514 1404 393

Answer:

12 1/2 laps

Step-by-step explanation:

To find the number of laps, divide the distance by the distance per lap.

(3 1/8) ÷ (1/4) = (3 1/8) × (4/1) = 3·4 +(1/8)·4 = 12 4/8 = 12 1/2

Quadir needs to jog 12 1/2 laps if he wants to jog 3 1/8 miles.

5 0

3 years ago

How do you round 25,386 to the nearest 1000

NeTakaya

You would round down to 25,000

3 0

3 years ago

Read 2 more answers

Last year at a certain high school, there were 50 boys on the honor roll and 75 girls on the honor roll. This year, the number o

Arturiano [62]

Answer:

About 15.3%!

Step-by-step explanation:

ill explain in comments, i hope this helps you out

6 0

2 years ago

Read 2 more answers

A nationwide study of American homeowners revealed that 65% have one or more lawn mowers. A lawnequipment manufacturer, located

GenaCL600 [577]

Answer:

$z=\frac{0.684 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.589$

$p_v =P(z>1.589)=0.056$

If we compare the p value obtained with the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of homes in Omaha with one or more lawn mowers is not ignificantly higher than 0.65

Step-by-step explanation:

Data given and notation

n=497 represent the random sample taken

X=340 represent the homes in Omaha with one or more lawn mowers

$\hat p=\frac{340}{497}=0.684$ estimated proportion of homes in Omaha with one or more lawn mowers

$p_o=0.65$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the true proportion of homes in Omaha with one or more lawn mowers is higher than 0.65.:

Null hypothesis: $p\leq 0.65$

Alternative hypothesis: $p > 0.65$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.684 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.589$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>1.589)=0.056$

If we compare the p value obtained with the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of homes in Omaha with one or more lawn mowers is not ignificantly higher than 0.65

7 0

3 years ago

(05.01)A scale drawing of a bathroom is shown below: A rectangle is shown. The length of the rectangle is labeled 2 inches. The

Nostrana [21]

2 by 3.5 is the area for the model.
Every 1 is meant to represent 20, so multiply both 2 and 3.5 by 20.
2 * 20 = 40
3.5 * 20 = 70
40 * 70 = 2800 in^2
Every 12 inches is 1 foot so divide 2800 by 12^2 (one square foot), or 144.
2800/144 = 19.44444
Round down because .4 is less than half.
Approximately 19 ft^2

8 0

3 years ago

Read 2 more answers