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3 years ago

PLEAAASEEE EXPLAIN THANK YOOOU:)))))

Mathematics

2 answers:

Harrizon [31]3 years ago

4 0

Here, we know, angle 1 and it's adjacent angle makes Linear pair equation, which means, there sum would be 180
We can see, angle 1 is obtuse means greater than 90 degree

In short, Your Answer would be Option A

Hope this helps!

Liula [17]3 years ago

3 0

Triangle is 180
therefore you have 180 > m<1 >56

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Hey help me plz!!!!!!!!!!!!!!!!!!!!!!

stira [4]

Step-by-step explanation:

Let's verify

$\\ \tt{:}\leadsto - \frac{1 }{3} x + 6 = - 6 + \frac{2}{3} x \\ \\ \tt{:}\leadsto 6 + 6 = \frac{2}{3} x + \frac{1}{3} x \\ \\ \tt{:}\leadsto 36 = \frac{3}{3} x \\ \\ \tt{:}\leadsto 36 = x$

<h3>Thus verified</h3>

3 0

3 years ago

The committee is planning a party and 180 guest are expected each bottle of juice contains enough for 16 servings how many bottl

inysia [295]

You will need 12 bottles of juice, but you will have some leftover because 16 does not go evenly into 180

3 0

4 years ago

My brain isn’t workin rn

aleksandr82 [10.1K]

Answer:

the green one under the orange one

Step-by-step explanation:

Parallel means never touching, and the 2 bases look like they never touch.

3 0

3 years ago

The 95% confidence interval for these parts is 56.98 to 57.05 under normal operations. A systematic sample is taken from the man

Nonamiya [84]

Answer:

Stop the line of production since the sample mean (56.96) is outside the confidence interval [ $CI_{0.95}$ = ( 56.98, 57.05 )]

Step-by-step explanation:

Given that;

95% confidence interval for these parts is 56.98 to 57.05

$CI_{0.95}$ = ( 56.98, 57.05 )

Sample mean = 56.96

We know that;

If the sample mean is within the confidence interval then, our decision is to keep the line operating as it is inside the confidence interval.

But if the sample mean is not within the confidence interval them, our decision is to stop the line of production as it is outside the confidence interval.

Now since our mean sample (56.96) does not lie between with the 95% confidence interval $CI_{0.95}$ = ( 56.98, 57.05 ).

Therefore, Stop the line of production since the sample mean (56.96) is outside the confidence interval [ $CI_{0.95}$ = ( 56.98, 57.05 )]

7 0

3 years ago

1)) Solve for t. t 1.28 > 5.5<br><img src="https://tex.z-dn.net/?f=1.28%20%5Cgeqslant%20%20%5Cfrac%7Bt%7D%7B5.5%7D%20" id="Te

Damm [24]

Answer:

x = 1.28t^2 > 5.5

8 0

2 years ago

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