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Anna71 [15]
3 years ago
10

A $17,000 T-bill is purchased at a 2.75% discount rate for 20 weeks.

Mathematics
1 answer:
SVEN [57.7K]3 years ago
3 0
The effective rate of interest to the nearest hundredth of a percent is 2.75%

Given:
T-bill value $17,000
purchased at a discount rate of 2.75%
term of 20 weeks.

An effective rate of interest is also referred as the DISCOUNT RATE, market interest rate, the internal rate of return, the annual percentage rate, and yield to maturity. 

Since the discount rate is given, it is also the effective rate of interest.
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Need help with this function problem
kotykmax [81]

Answer:

  see attached

Step-by-step explanation:

To find the inverse function, solve ...

  x = f(y)

  x = (y^7)/7 -4 . . . . . . . use the definition of f(x)

  x +4 = (y^7)/7 . . . . . . add 4

  7(x +4) = y^7 . . . . . . multiply by 7

  (7(x +4))^(1/7) = y . . take the 7th root

The inverse function is the one shown in the attachment.

4 0
2 years ago
Help please!!!!<br> Solve the system by graphing
kotegsom [21]

Answer:

picture of graph is attached. lmk if ur getting these right. its been a while since I've dont this

7 0
3 years ago
A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
Olenka [21]

Answer:

a

 The  90% confidence interval that  estimate the true proportion of students who receive financial aid is

     0.533  <  p <  0.64

b

   n = 1789

Step-by-step explanation:

Considering question a

From the question we are told that

      The sample size is  n = 200

      The number of student that receives financial aid is k = 118

Generally the sample proportion is  

      \^ p = \frac{k}{n}

=>   \^ p = \frac{118}{200}

=>   \^ p = 0.59

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of \frac{\alpha }{2}  is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

 =>E =  1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }

=>  E = 0.057

Generally 90% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

  =>  0.533  <  p <  0.64  

Considering question b

From the question we are told that

    The margin of error  is  E = 0.03

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the sample size is mathematically represented as      

        [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>      n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )

=>      n = 1789

8 0
3 years ago
Help gai I need help its a math
dem82 [27]

Answer:

B

Step-by-step explanation:

Rewriting in slope-intercept form.

x - 2y = 0

Add -x on both sides.

- 2y = 0 - x

Divide both sides by -2.

y = 0/-2 - x/-2

y = 0 - - 1/2x

y = 0 + 1/2x

y = 1/2x + 0

The slope is 1/2, the y-intercept is at (0, 0).

6 0
3 years ago
A line passes through the points (−4, −1) and (−2, −4) . Fill in the boxes to complete an equation for the line in point-slope f
gizmo_the_mogwai [7]
Here, first we need to calculate for Slope:
m = y2-y1 / x2-x1
m = -1-(-4) / -4-(-2)
m = 3 / -2
m = -3/2

Now, y - y1 = m(x - x1)
y + 1 = -3/2(x + 4)
y + 1 = -3/2x - 6
y = -3/2x - 7

In short, Your Equation would be: y = -3/2x - 7

Hope this helps!
8 0
3 years ago
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