The algebraic property demonstrated in the example below is Transitive Property of Equality. There we can see how the first thing is equal to the second one and notice that the first one is equal to the third one too. This is a Transitive Property of Equality in a nutshel.
The first reaction represented is a decomposition reaction due to the fact the bonded pair are being split apart.
The second equation is a single displacement because the B and C have switched places, which is the only change making it a single displacement. If there had been another bond and A had also moved, it would be double.
Answer:
should be 17
Step-by-step explanation:
Answer:
dh/dt ≈ 0.55 ft/min
Step-by-step explanation:
The volume is given by the formula ...
V = (1/3)πr²h
We have r = h/2, so the volume as a function of height is ...
V = (1/3)π(h/2)²h = (π/12)h³
Then the rates of change are related by ...
dV/dt = (π/4)h²·dh/dt
dh/dt = (4·dV/dt)/(πh²) = 4(35 ft³/min)/(π(9 ft)²)
dh/dt ≈ 0.55 ft/min
