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3 years ago

A quadilateral ABCD is drawn to circumcribe a circle . prove that AB+CD=AD+BC

Mathematics

2 answers:

gizmo_the_mogwai [7]3 years ago

6 0

Answer:

detail in steps

Step-by-step explanation:

as illustrated

AB = AP + BP

CD = CR + DR

AD = AS + DS

BC = BQ + CQ

while AP = AS BP = BQ CQ = CR DR = DS

AB + CD = AP + BP + CR + DR

AD+BC = AS + DS + BQ + CQ

∴ AB+CD=AD+BC

lora16 [44]3 years ago

3 0

Answer:

Helllllp

Step-by-step explanation:

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ryzh [129]

Answer:

Perimeter=25 units

Area= 43 units^2

Step-by-step explanation:

one side = 5 units so perimeter is 5x5=25

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area of each triangle =(5)(3.44)(0.5)=8.6

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3 years ago

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Orlov [11]

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Answer:

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Step-by-step explanation:

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3 years ago

Which sequence could be described by the explicit definition: t_n=2^n+1t n = 2 n + 1

yuradex [85]

Answer:

2. 27

3. Option C. 3, 5, 9, 17, 33, ...

Step-by-step explanation:

2. The sequence is defined by the explicit function $t_{n} = 2^{n} - n$

Therefore, the 5th term i.e. $t_{5}$ of the sequence.

$t_{5} = 2^{5} - 5 = 32 - 5 = 27$ (Answer)

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Hence, $t_{1} = 2^{1} + 1 = 3$

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3 years ago

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slega [8]

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