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3 years ago

A quadilateral ABCD is drawn to circumcribe a circle . prove that AB+CD=AD+BC

Mathematics

2 answers:

gizmo_the_mogwai [7]3 years ago

6 0

Answer:

detail in steps

Step-by-step explanation:

as illustrated

AB = AP + BP

CD = CR + DR

AD = AS + DS

BC = BQ + CQ

while AP = AS BP = BQ CQ = CR DR = DS

AB + CD = AP + BP + CR + DR

AD+BC = AS + DS + BQ + CQ

∴ AB+CD=AD+BC

lora16 [44]3 years ago

3 0

Answer:

Helllllp

Step-by-step explanation:

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What are the two equations that need to be solved to find the solutions for the absolute value equation |x-5|=x-2

Allushta [10]

Answer:

x - 5 = x - 2 and

x - 5 = 2 - x.

Step-by-step explanation:

x - 5 may be positive or negative so we have:

x - 5 = x - 2

and

x - 5 = - (x - 2)

x - 5 = 2 - x.

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3 years ago

Base = 5 ft Height= 3.5 ft what is the area

Advocard [28]

Answer:

the area is 17.5 ft if the shape is a square/rectangle

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Step-by-step explanation:

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3 years ago

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What kind of function is being illustrated by f(x)=|2x³-3x|+5?

Dimas [21]

Answer:

Option D: Absolute value function

Step-by-step explanation:

The absolute value of a number is the distance of the number from 0 to the left or right on the number line.

We are given the function;

f(x) = |2x³ - 3x| + 5

This function contains an absolute value symbol which is |2x³ - 3x|.

This function is thus illustrated by an an absolute value function because an absolute value function will be one that contains algebraic expressions within absolute value symbols.

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2 years ago

HELP ASAP IM IN A LIVE LESSON

Charra [1.4K]

Answer: 70 Degrees

Step-by-step explanation:

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2 years ago

The city has an average of 13 days of rainfall for April.

zhenek [66]

Using the Poisson distribution, we have that:

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

The parameters are:

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

For this problem, the mean is given as follows:

$\mu = 13$

The probability of having exactly 10 days of precipitation in the month of April is P(X = 10), hence:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 10) = \frac{e^{-13}13^{10}}{(10)!} = 0.0859$

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

The probability of having less than three days of precipitation in the month of April is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-13}13^{0}}{(0)!} \ approx 0$

$P(X = 1) = \frac{e^{-13}13^{1}}{(1)!} = 0.00003$

$P(X = 2) = \frac{e^{-13}13^{2}}{(2)!} = 0.00019$

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.00003 + 0.00019 = 0.00022

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

For more than 15 days, the probability is:

P(X > 15) = P(X = 16) + P(X = 17) + ... + P(X = 20)

Applying the formula for each of these values and adding them, we have that P(X > 15) = 0.2364, hence:

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

6 0

1 year ago