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3 years ago

I BEG U HELP ME!! Does each equation represent exponential decay or exponential growth?

Mathematics

1 answer:

ivolga24 [154]3 years ago

8 0

Answer:

see below

Step-by-step explanation:

If the base of the exponential term is greater than 1, it represents growth.

If the base of the exponential term is less than 1, it represent decay.

If there is no exponential term, the characterization as exponential growth or decay does not apply.

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members of a soccer team raised $741.15 to go to a tournament. They rented a bus for $250 and budgeted $25.85 per player for mea

blsea [12.9K]

9514 1404 393

Answer:

19 players

Step-by-step explanation:

The total being spent is ...

bus cost + (per player cost) × (number of players) = total raised

250 + 25.85p = 741.15

25.85p = 491.15

p = 491.15/25.85 = 19

The team could bring 19 players to the tournament.

6 0

2 years ago

Evaluate -2=y+5 and solve the variable

Rudiy27

Answer:

y=-7

Step-by-step explanation:

-2=y+5

-7=y

5 0

3 years ago

Read 2 more answers

5. The superintendent of the local school district claims that the children in her district are brighter, on average, than the g

anygoal [31]

Answer:

We conclude that children in district are brighter, on average, than the general population.

Step-by-step explanation:

We are given the following data set:

105, 109, 115, 112, 124, 115, 103, 110, 125, 99

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1117}{10} = 111.7$

Sum of squares of differences = 642.1

$S.D = \sqrt{\frac{642.1}{49}} = 8.44$

We are given the following in the question:

Population mean, μ = 106

Sample mean, $\bar{x}$ = 111.7

Sample size, n = 10

Alpha, α = 0.05

Sample standard deviation, s = 8.44

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 106\\H_A: \mu > 106$

We use one-tailed(right) t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{111.7 - 106}{\frac{8.44}{\sqrt{10}} } = 2.135$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = 1.833$

Since,

$t_{stat} > t_{critical}$

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

We conclude that children in district are brighter, on average, than the general population.

4 0

3 years ago

2÷9<br><img src="https://tex.z-dn.net/?f=78%20%5Csqrt%7B%7D%20" id="TexFormula1" title="78 \sqrt{} " alt="78 \sqrt{} " align="ab

dimulka [17.4K]

Answer:

2 ÷ 9 ≈ 0.222

√78 ≈ 8.832

3 0

3 years ago

In the following proportion, what does x equal?

trasher [3.6K]

A is the correct answer. 23/40=0.575 and 4.6/8= 0.575 as well.

6 0

3 years ago

Read 2 more answers