CD = 5 because they are congruent equilateral triangles
Answer:
Two differences: A polynomial inequality (PI) can always be replaced by a PI with one side zero. A rational inequality (RI) can not, because you do not know the sign of the denominator; a(x)b(x)>c(x)d(x) can not safely be replaced by a(x)d(x)−b(x)c(x)b(x)d(x)>0 because b(x) and/or d(x) might change signs unexpectedly.
Step-by-step explanation:
Answer:
No solution.
Step-by-step explanation:
![3^{\sqrt{m-4} } - 3^{\sqrt{2m + 8} }=0\\3^{\sqrt{m-4} } = 3^{\sqrt{2m + 8} }, so\\\sqrt{m-4} =\sqrt{2m + 8} \\m-4=2m+8\\2m-m=-4-8\\m=-12, but\\\sqrt{-4-8} =\sqrt{-12} , that \ is \ impossible \ for \ real\ numbers.\\So,\ no\ solution.](https://tex.z-dn.net/?f=3%5E%7B%5Csqrt%7Bm-4%7D%20%7D%20-%203%5E%7B%5Csqrt%7B2m%20%2B%208%7D%20%7D%3D0%5C%5C3%5E%7B%5Csqrt%7Bm-4%7D%20%7D%20%3D%203%5E%7B%5Csqrt%7B2m%20%2B%208%7D%20%7D%2C%20so%5C%5C%5Csqrt%7Bm-4%7D%20%3D%5Csqrt%7B2m%20%2B%208%7D%20%5C%5Cm-4%3D2m%2B8%5C%5C2m-m%3D-4-8%5C%5Cm%3D-12%2C%20but%5C%5C%5Csqrt%7B-4-8%7D%20%3D%5Csqrt%7B-12%7D%20%2C%20that%20%5C%20is%20%5C%20impossible%20%5C%20for%20%5C%20real%5C%20numbers.%5C%5CSo%2C%5C%20no%5C%20%20solution.)
Answer:
5
Step-by-step explanation:
EB is the median so it is the average of the top and bottom lengths
(38 + 6x-6) /2 = 7x-4
Combine like terms
(32+6x)/2 = 7x-4
Multiply by 2
32+6x = 14x-8
Subtract 6x from each side
32+6x-6x = 14x-6x -8
32 = 8x-8
Add 8 to each side
32+8 = 8x-8
40 = 8x
Divide by 8
40/8 = 8x/8
5 =x
You got the first part right
The theoretical probability is related to 1/2. A coin toss should always come up heads 1/2 the time and tails one 1/2 the time. So out of a class of 40 people, 20 people should flip (say) heads in theory and the other half of a class of 40 should flip tails 20 times.
Put more formally it looks like this.
P(sample) = Sample size * P(of it occurring once)
P(of it occurring once) = 1/2
Sample size = 40
P(sample) = 40 * 1/2
P(sample) = 20