Answer:
No, the child cannot inherit the disease.
Explanation:
The problem tells you that the man has a recessive allele for an inherited disease, but he has a normal phenotype. This means that the disease is recessive and in order for an individual to have the disease, they must have two recessive copies of the allele. The problem also tells you that the mother has a genotype that does not include this allele. With this information, you can do a punnet cross of BB (mother) x Bb (carrier father), and end up with the following possible genotypes: BB, Bb, BB, Bb. Therefore the child will not have the disease, but there is a 50% chance that the child will be a carrier for the disease.
Answer:
Sample Response: The first stage of cellular respiration occurs in the cytoplasm. This is where glucose is broken down into smaller molecules. A small amount of energy is also released. The second stage occurs in the mitochondrion. This is where the small molecules combine with oxygen to produce water, carbon dioxide, and a large amount of energy.
Explanation:
Answer:
I would say False. But not 100% sure.
Explanation:
Hope this helps you in some way.
Answer:
F1: Aa Bb Cc: 4.5 lbs
F2: Too many to list: Between 3 lbs and 6 lbs
Explanation:
F1: Aa Bb Cc, will be the genotypes and will weigh 4.5 lbs, the reason for that is because each capital letter allele adds half a pound to the base weight of 3 lbs.
F2: There are many different genotypes that can be present in the second generation, for example (AA BB CC, AA BB Cc, AA BB cc, etc.) each of which will allow the plant to grow to a certain height. The majority of phenotypes will be 4.5 lbs. There will be one who is AA BB CC, and another one person who has the code, aa bb cc.
