Answer:
x3(x+1)= –2(x-1)–4
3x^2+3x=–2x+2-4
3x^2+3x+2x=2-4
3x^2+5x=–2
3x^2+5x+2=0
3x^2+3x+2x+2=0
3x(x+1)2(x+1)=0
(3x+2)(x+1)=0
3x+2=0 or x+1=0
3x=–2 or x=–1
x=–2/3 or –1
Step-by-step explanation:
–remove brackets by multiplication
–form a quadratic equation
–and then solve either by means of quadratic formula or factorisation method
x= -1/3 or -2
3x^2 +3x= -2x +2-4
3x^2 + 5x +2=0
by factorization method
3x(x+2) 1(x+2)=0
(3x+1)(x+2)
Answer: prob 24
good luck!!
P = 8
slope: -1
y - 1= -(x + 4)
y - 1 = -x - 4
y = -x - 3
The first and third options are parallel.
They both have a slope of 2.
Pls mark brainliest. Thanks!
