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lara31 [8.8K]
3 years ago
7

What is the answer to 15÷9630?

Mathematics
1 answer:
Nesterboy [21]3 years ago
7 0

Answer:0.00155763

Step-by-step explanation:Use a calculator

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Name the following segment or point.
frutty [35]

Answer:

should be segment BT, that's what i put and it was right. hope this helps

Step-by-step explanation:

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3 years ago
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Does the following table shows a proportional relationship between the variables g & h​
KATRIN_1 [288]

*the table being referred to is attached below

Answer:

The table does not show a proportional relationship between variable g and h.

Step-by-step explanation:

For a proportional relationship to exist between two variables, there must be a constant, of which serves like a unit rate, when comparing two variables.

Thus, in the table attached below, there is no obvious constant of proportionality between variable g and variable h.

Thus, \frac{9}{3} ≠ \frac{36}{6} ≠ \frac{81}{9}

4 0
3 years ago
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(WILL GIVE BRAINLIEST) I NEED HELP ASAP!!!
aleksandr82 [10.1K]

Answer:

which ones do you need answered? all of them? want to help

Step-by-step explanation:

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3 years ago
One teacher wants to give each students 5/9of a slice of pizza. If the teacher has 15 slices of pizza,then how many students wil
valentina_108 [34]

Answer:

Step-by-step explanation:

10

5 0
3 years ago
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(I've been trying to figure this out for 3 days and I really need help)
liq [111]

Check the picture below.

since the diameter of the cone is 6", then its radius is half that or 3", so getting the volume of only the cone, not the top.

1)

\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \implies V\approx 37.7

2)

now, the top of it, as you notice in the picture, is a semicircle, whose radius is the same as the cone's, 3.

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=3 \end{cases}\implies V=\cfrac{4\pi (3)^3}{3}\implies V=36\pi \\\\\\ \stackrel{\textit{half of that for a semisphere}}{V=18\pi }\implies V\approx 56.55

3)

well, you'll be serving the cone and top combined, 12π + 18π = 30π or about 94.25 in³.

4)

pretty much the same thing, we get the volume of the cone and its top, add them up.

\bf \stackrel{\textit{cone's volume}}{\cfrac{\pi (3)^2(8)}{3}}~~~~+~~~~\stackrel{\stackrel{\textit{half a sphere}}{\textit{top's volume}}}{\cfrac{4\pi 3^3}{3}\div 2}\implies 24\pi +18\pi \implies 42\pi ~~\approx~~131.95~in^

8 0
3 years ago
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