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solmaris [256]
3 years ago
6

Roberto wants to display his 18 sports cards in an album. Some pages hold 2 cards and others hold 3 cards. How many different wa

ys can Roberto display his figures?
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
3 0
Let x = number of pages holding 2 cards,
y = number of pages holding 3 cards.

So his total number of card would be 2x + 3y, which is given as 18. So we get this equation.

2x + 3y = 18

Subtract 3y from both sides:

2x  = 18 – 3y

Divide both sides by 2:

x = (18 – 3y)/2

x must be an integer. So 18–3y must be a multiple of 2. Since 18 is a multiple of 2, 3y is also a multiple of 2. Then y must be a multiple of 2 too.

Let's start with y = 0.
When y = 0, x = (18 – 3(0))/2 = 9.
When y = 2, x = (18 – 3(2))/2 = 6.
When y = 4, x = (18 – 3(4))/2 = 3.
When y = 6, x = (18 – 3(6))/2 = 0.

Thus there are 4 ways to display his figures.

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Best explained and correct answer gets brainliest.
Zolol [24]
Your answer would be A because $4800 is your starting number and it increases 2% every year. How much is it in 20 years?

You use the formula ab^x
a is your starting number
b is the percentage
x is always the length of time

Since you are increasing and trying to get its worth larger than what it was before you use a number larger than one hundred percent in this case the number would be 1.02.


Y=4800(1.02)^20
Y=$7132.55

3 0
3 years ago
Me podrían ayudar y explicarme el proceso please
kakasveta [241]

Answer: Encontrarás las respuestas debajo de cada explicación. Espero que consideres darme brainliest y 5 estrellas, y más importante, que hayas entendido.

Step-by-step explanation:

Esto es la regla de 3. Conoces 3 valores y necesitas encontrar un 4to valor.

Ya sabemos que 1 caja pesa 20kg,

1 - 20kg

ahora queremos saber cuantas cajas (x) equivalen a 7653kg

x - 7653kg

Hacemos un pequeño cuadro poniendo en un lado los numeros de cajas y del otro el peso.

Pongamos la cantidad de cajas en la izquierda y el peso en la derecha

\frac{1}{x} =\frac{20kg}{7653kg}

Procedemos a multiplicar en cruz. Solo podemos multiplicar si tenemos ambos valores. En este caso, los valores en cruz que tenemos son 1 y 7653kg porque en la otra cruz (20 y x) tenemos nuestra incognita. Y, por ultimo, dividimos entre el numero cuya cruz es con la incognita (20kg)

Esto nos deja la expresión así;

x=\frac{1*7653kg}{20kg}

x=382.65

Como una caja no puede ser un numero decimal, redondeamos.

x=383

Por lo tanto, se necesitan aproximadamente 383 cajas para que su peso equivalga a 7653 kg.

-------------------------------------------------------------------------------------------------------

La otra pregunta dice: Si una caja pesa 20kg, (1 - 20kg), ¿Cuántas cajas se necesitan para equivaler 9500kg? (x - 9500kg)

Hacemos lo mismo que arriba, ponemos la cantidad de cajas de un lado, y el peso de otro lado.

\frac{1}{x}=\frac{20kg}{9500kg}

Multiplicamos aquellos valores en cruz que conozcamos y dividimos por el valor cuya cruz sea con x.

x=\frac{1*9500kg}{20kg}

x=475

Esta es la cantidad de cajas que se necesitan para que su pesa equivalga a 9500kg.

--------------------------------------------------------------------------------------------------------

Por último, la pregunta dice, ¿Cuántos kilogramos hay en 873 cajas?

Ya sabemos que una caja pesa 20kg ( 1 - 20kg ) y ahora buscamos cuantos kg hay en 873 cajas; es decir, (873 - x)

Nos quedaría así;

\frac{1}{873}=\frac{20kg}{x}

Ahora, nuestra cruz es 873 y 20kg, y el divisor es 1.

x=\frac{873*20kg}{1}

x=17460kg

Este sería el peso de 873 cajas.

5 0
3 years ago
2/3x+5=1 what is the solution to the equation shown?
Fudgin [204]

Answer:

x = - 6

Step-by-step explanation:

Given

\frac{2}{3} x + 5 = 1 ( subtract 5 from both sides )

\frac{2}{3} x = - 4

Multiply both sides by 3 to clear the fraction

2x = - 12 ( divide both sides by 2 )

x = - 6

7 0
4 years ago
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Katyanochek1 [597]

(0,416, infinity) is the best answer

Thank you for your question, <u>your question is: The amount of algae in a bloom, P, can be modeled by the equation P = t4 + 6t3 + 7t2 + 8t, where t is measured in weeks. When will the population of algae be greater than 500?</u>

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4 years ago
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PLEASE HELP!!<br><br> Find the area of the sector.
Lunna [17]

Answer:

B.

\frac{275\pi}{6}  {m}^{2}

Step-by-step explanation:

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