Let
x---------> the length side of the rectangular area
y---------> the width side of the rectangular area
we know that
the area of the rectangle is equal to

-----> equation 
The perimeter of the rectangle is equal to

but remember that the fourth side of the rectangle will be formed by a portion of the barn wall
so
-----> equation 
<em>To minimize the cost we must minimize the perimeter</em>
Substitute the equation
in the equation 
![P=x+2*[\frac{200}{x} ]](https://tex.z-dn.net/?f=%20P%3Dx%2B2%2A%5B%5Cfrac%7B200%7D%7Bx%7D%20%20%5D%20)
Using a graph tool
see the attached figure
The minimum of the graph is the point 
that means for 
the perimeter is a minimum and equal to 
<u>Find the value of y</u>



The cost of fencing is equal to

therefore
<u>the answer is</u>
the length side of the the fourth wall will be 
Answer:
adult tickets 6.9
children tickets 3.9
Step-by-step explanation:
3x + y = 24.60 L1
5x + 4y = 50.10 L2
5L1 - 3L2
15x + 5y = 123
-15x - 12y = -150.3
-7y = -27,3
y = -27,3/-7
y = 3.9
3x + y = 24.60
3x + 3.9 = 24.60
3x = 24.60 - 3.9
3x = 20.7
x = 20.7 / 3
x = 6.9
4/9
percent = 44%
decimal = 0.4(4 is repeating)
Let's take the number as x.
two-fifths of a number = 2x / 5
decreased by 3 = (2x/5) - 3
(2x/5) - 3
(2*25/5) - 3
(2*5) - 3
10 - 3
7