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3 years ago

13

Jocelyn writes the equation of a line that passes through the point (4,0) and that is perpendicular to the line y= -2X + 1. IF J

ocelyn write her equation in the form y= MX +B, what is the value of B?

1 answer:

raketka [301]3 years ago

6 0

Y = 2x - 8
I used a graphing calculator to figure it out.

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I need help on my math

shtirl [24]

Answer:

y = -5/4x - 4

Step-by-step explanation:

The equation they give you is in slope intercept form. y=mx+b. The m is the slope (-5/4). Since they want a parallel line you keep the same slope for point slope form. Point slope formula is y-y1=m(x-x1). the y1 and x1 are where you plug in the coordinates they give you.

y - 1 = -5/4x (x + 4)

y - 1 = -5/4x - 5

y = -5/4x - 4

4 0

3 years ago

A home is to be built on a 56 foot 9 inch wide lot. The house is 5 feet 5 inches from the side of the lot and is 34 feet 10 inch

Anni [7]

Check the picture below, so the distance of the house from the other side is that blue gap.

so, there are 12 inches in 1 foot, so let's just convert all those feet to inches and subtract them.

$\bf 56'\implies (56\cdot 12)''\implies 672''
\\\\\\
5'5''\implies (5\cdot 12+5)''\implies 65''
\\\\\\
34'10''\implies (34\cdot 12 + 10)''\implies 418''\\\\
-------------------------------\\\\
672''-(65+418)''\implies 189''\implies 15'9''$

6 0

2 years ago

Read 2 more answers

How many whole servings of 3/4 cups are in 31/2 cups of ice cream?

IrinaVladis [17]

20 servings :) You multiply the 31/2 by 2 then divide 62 by 3 and thats your answer

6 0

2 years ago

Read 2 more answers

How many extraneous solutions does the equation below have?

aev [14]

Answer:

A solution is said to be extraneous, if it is a zero of the equation, but it does not satisfy the equation,when substituted in the original equation,L.H.S≠R.H.S.

The given equation consisting of variable , m is

$\frac{2 m}{2 m+3} -\frac{2 m}{2 m-3}=1\\\\ 2 m[\frac{1}{2 m+3} -\frac{1}{2 m-3}]=1\\\\ 2 m\times \frac{[2 m-3 -2 m- 3]}{4m^2-9}=1\\\\ -6 \times 2 m=4 m^2 -9\\\\ 4 m^2 +1 2 m -9=0\\\\m=\frac{-12 \pm\sqrt{12^2-4 \times 4 \times (-9)}}{2\times 4}\\\\m=\frac{-12 \pm \sqrt {144+144}}{8}\\\\m=\frac{-12 \pm \sqrt {288}}{8}\\\\m=\frac{-12 \pm 12 \sqrt{2}}{8}\\\\m=\frac{3}{2}\times(-1 \pm \sqrt{2})$

None of the two solution

$m=\frac{3}{2}\times(-1 +\sqrt{2}) and , m=\frac{3}{2}\times(-1 -\sqrt{2})$ , is extraneous.

Here, L.H.S= R.H.S

Option A: 0→ extraneous

8 0

2 years ago

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Need Help!!!!!!!!!!!!!

zepelin [54]

the thing to do here is multiply base and height in this case 2yd and 2.3yd, that's how I would solve it.

3 0

2 years ago