well the triangles are congruent so that equation has to equal 61, so set it equal to 61, once you do that subtract 10 with 61 giving you 51, then divide 3 with 51 and you get 17

$3x + 10 = 61 \\ 3x = 51 \\ x = 17$

3 0

3 years ago

Given the following exponential function, identify whether the change represents growth or decay, and determine the percentage r

postnew [5]

Answer: -34738.4259228

Step-by-step explanation:

It’s a decrease because your dividing 1600e -0.1252

5 0

3 years ago

What is the<br> area of the rhombus?

cluponka [151]

Answer:

Area=36

Step-by-step explanation:

Area of rhombus: diagonal 1 x diagonal 2 divided by 2.

To find the area of a rhombus, you need to find the length of both diagonals(which is the distance between 2 points across from each other).

First, find the distance between -8 and 4 which is 12.

Next, find the distance between -1 and -7 which is 6.

12 x 6 =72

72/2=36

4 0

3 years ago

Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

5 0

3 years ago