The length of the rectangle is 60 feet and the width of the rectangle is 45 feet.
<h3>What is the area of the rectangle?</h3>
Let L be the length and W be the width of the rectangle.
Then the area of the rectangle will be
Area of the rectangle = L×W square units
A farmer’s rectangular pen has an area of 2,700 square feet, and the width is 15 feet shorter than the length.
L = W + 15
Then we have
2700 = W(W + 15)
W² + 15W - 2700 = 0
W² + 60W - 45W - 2700 = 0
(W + 60)(W - 45) = 0
W = 45, -60
Then the dimension of the rectangle will be
W = 45 feet
L = W + 15
L = 45 + 15
L = 60 feet
More about the area of the rectangle link is given below.
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It would be 220 rounded to the nearest ten because the number in the ones place does not equal or exceed 5.
So 220 is your answer :)
Answer:
a= 200
b = 210
Step-by-step explanation:
My assumption is, we have to find the length of sides of rectangle
Given
perimeter = 2a + 2b = 820 ft (i) (here a is smaller side and b is larger side)
area = a*b = 42,000 ft^2 (ii)
from eq (1)
2a + 2b = 820
=> 2(a+b) = 820
=> a+b = 820/2
=> a + b = 410
=> a = 410-b (iii)
putting the value of a in eq(ii), we get
(410-b) *b = 42,000
410b - b^2 = 42,000
0 = b^2 - 410b + 42000
b^2 - 410b + 42000 = 0
b^2- 200b- 210b + 42000 = 0
b(b-200)-210(b-200) = 0
(b-200)(b-210) = 0
or
b= 210 and b = 200
if b is larger side than b =210
By putting value of b in eq(iii),
a = 410 -210 = 200
The anser is 20 that what i think
Answer:
43
Step-by-step explanation:
if EF(part) = 18 and DF(the whole line) = 61
61-18 is 43. 43=DE
Please give brainliest thanks
