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r-ruslan [8.4K]
3 years ago
8

What is the slope of the line graphed below (-3,5) (6,-1)

Mathematics
2 answers:
-Dominant- [34]3 years ago
6 0
-2/3x is the slope because the equation is y=-2/3x + 3
Zinaida [17]3 years ago
5 0
Rise over run so x2-x1 / y2-y1
9/6=3/2
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Simplify the Expression(20 points)-<br> -m - 7m
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Answer:

-8m

Step-by-step explanation:

Combine like terms

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3 years ago
Please help me answer this
horsena [70]

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Step-by-step explanation:

7 0
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Factor the quadratic expression. Write the factors as a product of two binomials.<br><br> x² - 7x-8
Aloiza [94]
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3 0
3 years ago
IS 3.
coldgirl [10]

Answer:

1. a. 2,000

2. b. 10 years

3. a. 6.72937

4. d. 9%

Step-by-step explanation:

1. If 58% are boys, the percentage of girls is:

= 100 - 58

= 42%

That means 840 is 42% of the students in class. The students in class are therefore:

= 840 / 42%

= 2,000 students

2. If Birr 300 is invested at 6% per year, the amount in interest it earns per year is:

= 300 * 6%

= Birr 18

To get to Birr 180, it would take:

= 180/18

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= 672.937/100

= 6.72937

4. The investment accrued Birr 12 out of Birr 400 in 4 months. This means that it increased by:

= 12/400

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6 0
3 years ago
Solving radical equations
My name is Ann [436]

Answer:

  • top: no solution
  • bottom: x = 7

Step-by-step explanation:

I find a graphing calculator very helpful to solving radical equations. It helps avoid extraneous solutions.

<u>top</u>

  √(-14x +2) = x -3

  -14x +2 = x² -6x +9 . . . . . square both sides

  x² +8x +7 = 0 . . . . . . . . . .subtract the left side

Descartes' rule of signs tells you this has no positive real solutions. (There are no sign changes among the coefficients.) The value of the radical will be non-negative, so we must have x-3≥0, or x≥3. Since there are no positive real solutions to the quadratic, there are no values of x≥3 that will satisfy the equation. NO SOLUTION

__

<u>bottom</u>

  4√(x -3) = 8 . . . . . given

  √(x -3) = 2 . . . . . . divide by 4

  x -3 = 4 . . . . . . . . . square both sides

  x = 7 . . . . . . . . . . . add 3

3 0
4 years ago
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