First you would divide 48 by 4 which equals 12.
after this you are left with 15-?=12.
?=3
Answer:
0.15 = 15% probability that a randomly selected passenger has a waiting time greater than 4.25 minutes.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:
![P(X > x) = \frac{b - x}{b - a}](https://tex.z-dn.net/?f=P%28X%20%3E%20x%29%20%3D%20%5Cfrac%7Bb%20-%20x%7D%7Bb%20-%20a%7D)
Uniformly distributed between 0 and 5 minutes.
This means that ![a = 0, b = 5](https://tex.z-dn.net/?f=a%20%3D%200%2C%20b%20%3D%205)
Find the probability that a randomly selected passenger has a waiting time greater than 4.25 minutes.
![P(X > 4.25) = \frac{5 - 4.25}{5 - 0} = 0.15](https://tex.z-dn.net/?f=P%28X%20%3E%204.25%29%20%3D%20%5Cfrac%7B5%20-%204.25%7D%7B5%20-%200%7D%20%3D%200.15)
0.15 = 15% probability that a randomly selected passenger has a waiting time greater than 4.25 minutes.
12. 32
6*2. 8*4
3*2*2. 4*2 2*2
2*2*2*2*2
Do the rest of the math yourself lol