3 years ago

Estimate the quotient 338.7÷49

Mathematics

1 answer:

Talja [164]3 years ago

4 0

Answer:

340/50=6.8

Step-by-step explanation:

338.7=340

49=50

=6.8

You might be interested in

Find the distance of the line segment joining the two points (-4 /2 - /12) and (/32, 2/3)

astraxan [27]

Answer: $4\sqrt{3}$ .

Step-by-step explanation:

Distance formula : Distance between points (a,b) and (c,d) is given by :-

$D=\sqrt{(d-b)^2+(b-a)^2}$

Distance between points $(-4\sqrt{2},\sqrt{12}) \text{ and }(-\sqrt{32}, 2\sqrt{3})$ .

$D=\sqrt{(2\sqrt{3}-(-\sqrt{12}))^2+(-\sqrt{32}-(-4\sqrt{2}))}\\\\=\sqrt{(2\sqrt{3}+\sqrt{2\times2\times3})^2+(-\sqrt{4\times4\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}-\sqrt{2^2\times3})^2+(-\sqrt{4^2\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}+2\sqrt{3})^2+(-4\sqrt{2}+4\sqrt{2})^2}\\\\=\sqrt{(4\sqrt{3})^2+0}\\\\=4\sqrt{3}\text{ units}$

Hence, the correct option is $4\sqrt{3}$ .

3 0

3 years ago

2. If you used the 23 cm basketball as your Moon sphere, how big

castortr0y [4]

Ok so I heard this question a few times already and couldn't remember how it went so I decided to put my brain to the test, I used my algebra to use and complete it.

If the Earth were shrunk down to the size of a basketball (radius:4.69 inches) the Moon would be a tennis ball (radius: 1.2768 inches, to be exact) 23.5 feet away.

The Sun would be a 42.6-foot sphere (source) located 1.7 miles away.

The closest star, Proxima Centauri, would still be 463,151 miles away – almost twice the distance of the actual moon."

6 0

3 years ago

Select all the expressions that are equivalent to 16x+36

kakasveta [241]

I believe it’s c and d

3 0

3 years ago

Read 2 more answers

If f(x)= 3x + 1 what is is the value of x when f(x)= 15

astraxan [27]