If x=-5 is a zero, then the first factor of the polynomial would be (x + 5 )
To find the other two factors we can divide the polynomial by the expression (x+5).
Using synthetic division, we have:
-5 I 4 15 -24 5 (Coefficients of the dividend)
I -20 25 -5 (Multiplying each coefficient by the results of the substraction and adding)
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4 -5 1 0 (Coefficients of the quotient)
The result of the division is 4x^2 - 5x + 1. Factoring it, we have:
4x^2 - 4x -x + 1 (Separating -5x into -x and -4x)
4x (x - 1) - (x -1) (Factoring each pair of terms)
(x-1)(4x-1) (Factoring using the common factor)
So the answer would be:
(x + 5 )(x-1)(4x-1)
Answer:
Let p be the number of pencils.
3(14-p)=30+p
42-3p=30+p
4p=12, p=3.
So Peter ends up with 33 and Tony with 11. 3*11=33, so that confirms that Tony gave Peter 3 pencils.
Answer:
Jim had 1/3 of of the pizza
Step-by-step explanation:
He shared a pizza with four friends, each friend had a Piece that was the same size as the other pieces, Jim had TWICE as much pizza as his friends so He had 2 pieces since he has 4 friends and each has 1 piece, so 4 + 2 = 6
2/6 simplify if, 1/3.
The answer is B, C, and D. Like terms are terms with all the same variable, so 5x and -x are like terms.
C is correct. If we add -x to 5x, we get 4x. The other numbers remain unchanged because they have no like terms.
D is correct. Applying the rule of like terms, which is that like terms are numbers with the same variable, only add together numbers with the same variable.
stay safe!! wash ur hands and wear a mask :D
Answer:
Median.
Step-by-step explanation:
We have been given that in 2004, the mean net worth of families in a certain region was $470.2 thousand and the median net worth was $92.3 thousand.
We know that mean and median of a symmetric data set is equal.
We also know that when mean of a data set is greater than median, then the data set has a very large valued outlier.
Since mean net wroth of families is approximately 5 times more than median net wroth of families, this means that some of the families has very high net worth as outliers.
Since the net worth of families has very large outliers, therefore, I would prefer median as the appropriate measure of center as median is not affected by outliers.