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Rzqust [24]
3 years ago
5

A square that is 5yd on a side is placed inside a rectangle that has a width of 11yd and a length of 17 yd. What is the area of

the region inside the rectangle that surrounds the square?
Mathematics
1 answer:
Anit [1.1K]3 years ago
5 0

Answer: 162  sq. yds.

Step-by-step explanation:

Given : A square that is 5yd on a side is placed inside a rectangle that has a width of 11yd and a length of 17 yd.

Then , Area of rectangle = length x width

= 11 yd  x 17 yd = 187 sq. yds.

Area of square = (side)²  

= (5 yd)² = 25  sq. yds.

Now , the area of the region inside the rectangle that surrounds the square will be Area of rectangle - Area of square

= 187 sq. yds.- 25  sq. yds.

=162  sq. yds.

Hence, the area of the region inside the rectangle that surrounds the square is 162  sq. yds. .

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B. 4x + 20 > 55

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3) Valerie works at a local amusement park. She earns $9.80 per hour. She 20 points
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<h3>Answer:  Choice A</h3><h3>9.80h+10 = 88.40</h3>

===========================================================

Work Shown:

  • h = number of hours worked.
  • 9.80h = amount of money earned after working h number of hours (ignoring the meal bonus).
  • 9.80h+10 = total amount of money earned after adding on the meal bonus.
  • 9.80h+10 = 88.40 is the equation we use since the total 9.80h+10 is the same as the total she earned 88.40 dollars.

--------------------

Extra info (optional section)

If you want to solve for h, then you could follow these steps.

9.80h+10 = 88.40

9.80h = 88.40-10 ... subtract 10 from both sides

9.80h = 78.40

h = 78.40/9.80 .... divide both sides by 9.80

h = 8

Valerie worked 8 hours on Friday.

As a check,

9.80h + 10 = 88.40

9.80*8 + 10 = 88.40

78.40 + 10 = 88.40

88.40 = 88.40

The answer is confirmed.

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