1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GenaCL600 [577]
3 years ago
5

maria spent 15 days traveling in south america.how many hours did she spend traveling in south america

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
4 0
It is said that she spent 15 days travelling to south america. 
Now the question is how many hours is 15 days that she spent travelling to reach south america?
=> in every 1 day = 24 hours.
=> 24 hours * 15 days = 360 hours,
She spent 360 hours to get to south america.
You might be interested in
Write the quadratic function f(x) = 3(x + 1)(x – 7) in standard form.
Sveta_85 [38]

Answer:

B

Step-by-step explanation:

Given

f(x) = 3(x + 1)(x - 7) ← expand the factors using FOIL

     = 3(x² - 6x - 7) ← distribute the parenthesis

      = 3x² - 18x - 21 → B

4 0
3 years ago
How should I explain how I know that 984/616 = 123/77 ?
Anon25 [30]

True they are equal

Step-by-step explanation:

123/77=

123×8/77×8

=984/616

6 0
3 years ago
Suppose you performed this experiment, and the percentage difference from the accepted value of the density of copper and your v
GREYUIT [131]

Answer:

The answer is 2%

Step-by-step explanation:

Steps to Calculate the Percent Error

Subtract the accepted value from the experimental value.

Take the absolute value of step 1

Divide that answer by the accepted value.

Multiply that answer by 100 and add the % symbol to express the answer as a percentage.

Now let’s try an example problem.

You are given a cube of pure copper. You measure the sides of the cube to find the volume and weigh it to find its mass. When you calculate the density using your measurements, you get 8.78 grams/cm3. Copper’s accepted density is 8.96 g/cm3. What is your percent error?

Solution:

experimental value = 8.78 g/cm3

accepted value = 8.96 g/cm3

Step 1: Subtract the accepted value from the experimental value.

8.78 g/cm3 – 8.96 g/cm3 = -0.18 g/cm3

Step 2: Take the absolute value of step 1

|-0.18 g/cm3| = 0.18 g/cm3

Step 3: Divide that answer by the accepted value.Percent Error Math 3

Step 4: Multiply that answer by 100 and add the % symbol to express the answer as a percentage.

0.02 x 100 = 2

2%

The percent error of your density calculation was 2%.

8 0
3 years ago
Which describes the correct order of steps for constructing an angle bisector of ∠DEF using only a straightedge and compass?
lana66690 [7]

You would want to make an equilateral triangle and draw a line from E to the vertex, so the correct answer should be A.

6 0
3 years ago
Read 2 more answers
ASAP HELP ME PLEASE<br>2,3,4,5,6,7,8
GrogVix [38]
The answer for number 2 is 1/4
3 0
3 years ago
Read 2 more answers
Other questions:
  • An electron is released from rest in a uniform electric field. the electron accelerates vertically upward, traveling 4.50m in th
    14·1 answer
  • Can someone help me with these questions??
    15·1 answer
  • Write a function to represent the set of ordered pairs. {(2, -2), (3, 8), (4, 22), (5, 40)} A) f(x) = -x B) f(x) = x - 4 C) f(x)
    8·1 answer
  • a cell phone company is giving a 20℅ discount on all phone accessories which expression can used to find the sale price of an it
    8·1 answer
  • Find an equation for the line that passes through the points , −3−1 and , 5,5 .
    10·1 answer
  • The box plots below show the distribution of salaries, in thousands, among employees of two small companies.
    8·2 answers
  • What is the degree of the equation?
    6·2 answers
  • Can someone help me with 9,10, and 11 please you don’t have to do all of them just atleast one for me
    7·2 answers
  • Let f (x) represent a function.
    6·2 answers
  • From midnight to 10:00 am, the temperature dropped
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!