The slope of a line is always zero because the line does not move up or down on the y-axis.
I'm assuming all of (x^2+9) is in the denominator. If that assumption is correct, then,
One possible answer is 
Another possible answer is 
There are many ways to do this. The idea is that when we have f( g(x) ), we basically replace every x in f(x) with g(x)
So in the first example above, we would have

In that third step, g(x) was replaced with x^2+9 since g(x) = x^2+9.
Similar steps will happen with the second example as well (when g(x) = x^2)
X2 - 8x + 15 = 0
(x - 3)(x - 5) = 0
critical points are at 3 and 5
Answer:
a = 10, b = 6, c = 2, d = 0
Step-by-step explanation:
Substitute the appropriate values of x into the equation and evaluate
x = - 3 : y = 4 - 2(- 3) = 4 + 6 = 10 → a
x = - 1 : y = 4 - 2(- 1) = 4 + 2 = 6 → b
x = 1 : y = 4 - 2(1) = 4 - 2 = 2 → c
x = 2 : y = 4 - 2(2) = 4 - 4 = 0 → d