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3 years ago

In each of these situations light refracts, except for one. Identify the case in which light is NOT refracted.

Mathematics

2 answers:

ipn [44]3 years ago

8 0

B) ...............................

Eva8 [605]3 years ago

3 0

B) sunlight travels through space - there is nothing to bounce off of until it hits an atmophere

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Are y = 6x + 9 and 27x – 3y = –81 parallel

jonny [76]

Nope, those lines are not parallel.

8 0

3 years ago

A contractor purchases 4 dozen pairs of padded work gloves for $56.16. She incorrectly calculates the unit price as $14.04 per

8090 [49]

Answer:

The correct unit price is $1.17 per pair of gloves. The error is she used number of dozens so, firstly convert it to number of pairs of gloves then divide.

Step-by-step explanation:

It is given 4 dozen pairs of gloves for $56.16.

So, unit price = Divide the price by number of pairs of gloves.

And 1 dozen =12

So 4 dozen =4*12=48 pairs of gloves

So, to find unit rate divide 56.16 by 48.

Unit price = $\frac{56.16}{48}= $1.17$

So, the error is she didn't convert the dozen to units.

That made mistake in finding unit price.

6 0

3 years ago

Find the value of a in the parallelogram. (a, AB, BC, CD, AD). Pls show work

kirill [66]

Step-by-step explanation:

Hope it will helps you..

Your photo is so unclear ..but i try my best to understand...

8 0

2 years ago

Chloe received 86% on her first test, a 47/50 in her next test, and a 0.89 on her third test. List her percentages in order from

Mumz [18]

Answer:

84%, 86%, 89%

Step-by-step explanation:

The three numbers, expressed as percentages, are ...

86%
(47/50)×100% = 84%
0.89×100% = 89%

Smallest to largest, they are 84%, 86%, and 89%. In the original form, they are 47/50, 86%, and 0.89.

7 0

3 years ago

Perform the indicated operation.(3/a+2) + (4/a-5)

kipiarov [429]

Answer:

$\frac{7(a-1)}{(a+2)(a-5)}$

Step-by-step explanation:

To solve this operation we need to find the common multiple of both denominators and solve for a.

$\frac{3}{a+2} + \frac{4}{a-5} =\frac{3(a-5)+4(a+2)}{(a+2)(a-5)} =\frac{3a-15+4a+8}{(a+2)(a-5)} =\frac{7a-7}{(a+2)(a-5)} =\frac{7(a-1)}{(a+2)(a-5)}$

Thus, the solution is 7(a -1) / (a+2)(a-5)

8 0

3 years ago