2 years ago

In each of these situations light refracts, except for one. Identify the case in which light is NOT refracted.

Mathematics

2 answers:

ipn [44]2 years ago

8 0

B) ...............................

Eva8 [605]2 years ago

3 0

B) sunlight travels through space - there is nothing to bounce off of until it hits an atmophere

You might be interested in

Find the slope of (4,-1) and (6,2) show work pls

natka813 [3]

Answer:

The slope is 3/2

Step-by-step explanation:

I put both coordinates into MathPapa and it told me that that's the slope

6 0

2 years ago

An item is priced at $13.57. If the sales tax is 7%, what does the item cost including sales tax?

cluponka [151]

Answer:

14.52

Step-by-step explanation:

13.57 + 13.57 x 7% = 13.57 x (1+7/100) =13.57 x 107/100 = 14.52

5 0

3 years ago

Write (8a-^3) -2/3 in simplest form

Anna71 [15]

$(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Solution:

Given that,

$(8a^{-3})^{\frac{-2}{3}$

We have to write in simplest form

Use the following law of exponent

$(a^m)^n = a^{mn}$

Using this, simplify the given expression

$(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$