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Alinara [238K]
3 years ago
7

Mon wants to make 5 lbs of the sugar syrup. How much water and how much sugar does he need to make 75% syrup?

Mathematics
1 answer:
Julli [10]3 years ago
7 0

Answer:

He needs 3.75 lbs of sugar and 1.25 lbs of water.

Step-by-step explanation:

Let x lbs be the amount of sugar in the syrup. Then 5-x lbs is the amount of water in this syrup.

Note

5 lbs - 100%

x lbs - 75%

Write a proportion:

\dfrac{5}{x}=\dfrac{100}{75}

Cross multiply:

100x=5\cdot 75\\ \\100x=375\\ \\x=\dfrac{375}{100}=3.75

So, he needs 3.75 lbs of sugar and 5 - 3.75 = 1.25 lbs of water.

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1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)
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Answer:

1. -5x+3y+44=0

2. 2x+y-2=0

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Step-by-step explanation:

Standard form of a line is Ax+By+C=0.

If a line passing through two points then the equation of line is

y-y_1=m(x-x_1)

where, m is slope, i.e.,m=\dfrac{y_2-y_1}{x_2-x_1}.

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)

y+3=\dfrac{-5}{-3}(x-7)

y+3=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

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-5x+3y+44=0

Therefore, the required equation is -5x+3y+44=0.

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to 2 x + y =-5.

Slope of the line : m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

y-2=-2(x-0)

y-2=-2x

2x+y-2=0

Therefore, the required equation is 2x+y-2=0.

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y =-5.

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

y-0=-2(x-2)

y=-2x+4

2x+y-4=0

Therefore, the required equation is 2x+y-4=0.

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