Answer:
A = 6 units ^2
Step-by-step explanation:
Let the base of the triangle be DE. Its length is 3 units
Let the height of the triangle be from DE to point F. That is 4 units ( -3 to 1 is 4 units)
The area of the triangle is
A = 1/2 bh
=1/2 (3)(4)
A = 6 units ^2
Well, let's first solve each equation:
1.) -4x + 6 - 3x = 12 - 2x - 3x
To start, combine each like-term on each side of the equal sign (The numbers with variables in-common // the numbers alike on the same side of the equal sign):
-7x + 6 = 12 - 5x
Now, we get the two terms with variables attached to them, on the same side, so, we do the opposite of subtraction, which is, addition:
-7x + 6 = 12 - 5x
+5x +5x
_____________
-2x + 6 = 12
Next, you do the opposite of addition, which is, subtraction, and, subtract 6 from both sides:
-2x + 6 = 12
-6 -6
____________
-2x = 6
Finally, divide by -2 on each side, to find out what the value of 'x' is:
-2x = 6
÷-2 ÷-2
________
x = -3
So, the answer is not 'A.'
_________________________________________
Now, we test out the rest of the equations, the exact same way:
2.) 4x + 6 + 3x = 12 + 2x + 3x
Combine your like-terms, on each side of the equal sign:
7x + 6 = 12 + 5x
Now, get both terms, with the variable, 'x,' to the same side, and, to do that, do the opposite of addition, which is, subtraction:
7x + 6 = 12 + 5x
-5x -5x
______________
2x + 6 = 12
Next, subtract 6 from both sides:
2x + 6 = 12
-6 -6
__________
2x = 6
Finally, divide by 2, on both sides:
2x = 6
÷2 ÷2
__________
x = 3
So, the answer is 'B.'
_________________________________________
3.) 4x + 6 - 3x = 12 - 2x - 3x
Again, we combine the like-terms, on both sides of the equal sign:
x + 6 = 12 - 5x
Now, we get both terms with the variable 'x,' to the same side, and, the opposite of subtraction, is addition, so, we're going to add 5x to both sides:
x + 6 = 12 - 5x
+ 5x + 5x
______________
6x + 6 = 12
Now, we subtract 6 from each side, because, the opposite of addition, is subtraction:
6x + 6 = 12
- 6 - 6
_____________
6x = 6
Now, divide by 6, on both sides:
6x = 6
÷ 6 ÷ 6
_____________
x = 1
So, the answer is not 'C.'
_________________________________________
4.) 4x + 6 - 3x = 12x + 2x + 3x
First, we combine the like-terms:
x + 6 = 17x
Next, we get both terms, with the variable, 'x,' to the same side:
x + 6 = 17x
-x -x
_____________
6 = 16x
Now, divide by 16, on both sides:
X = 3/8
So, 'D,' is not the answer.
_______________________
The answer is, 'B.'
I hope this helps!
Answer:
See explanation
Step-by-step explanation:
Simplify left and right parts separately.
<u>Left part:</u>
![\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}](https://tex.z-dn.net/?f=%5Cleft%281%2B%5Cdfrac%7B1%7D%7B%5Ctan%5E2A%7D%5Cright%29%5Cleft%281%2B%5Cdfrac%7B1%7D%7B%5Ccot%20%5E2A%7D%5Cright%29%5C%5C%20%5C%5C%3D%5Cleft%281%2B%5Cdfrac%7B1%7D%7B%5Cfrac%7B%5Csin%5E2A%7D%7B%5Ccos%5E2A%7D%7D%5Cright%29%5Cleft%281%2B%5Cdfrac%7B1%7D%7B%5Cfrac%7B%5Ccos%5E2A%7D%7B%5Csin%5E2A%7D%7D%5Cright%29%5C%5C%20%5C%5C%3D%5Cleft%281%2B%5Cdfrac%7B%5Ccos%5E2A%7D%7B%5Csin%5E2A%7D%5Cright%29%5Cleft%281%2B%5Cdfrac%7B%5Csin%5E2A%7D%7B%5Ccos%5E2A%7D%5Cright%29%5C%5C%20%5C%5C%3D%5Cdfrac%7B%5Csin%5E2A%2B%5Ccos%5E2A%7D%7B%5Csin%5E2A%7D%5Ccdot%20%5Cdfrac%7B%5Ccos%5E2A%2B%5Csin%5EA%7D%7B%5Ccos%5E2A%7D%5C%5C%20%5C%5C%3D%5Cdfrac%7B1%7D%7B%5Csin%5E2A%7D%5Ccdot%20%5Cdfrac%7B1%7D%7B%5Ccos%5E2A%7D%5C%5C%20%5C%5C%3D%5Cdfrac%7B1%7D%7B%5Csin%5E2A%5Ccos%5E2A%7D)
<u>Right part:</u>
![\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B%5Csin%5E2A-%5Csin%5E4A%7D%5C%5C%20%5C%5C%3D%5Cdfrac%7B1%7D%7B%5Csin%5E2A%281-%5Csin%5E2A%29%7D%5C%5C%20%5C%5C%3D%5Cdfrac%7B1%7D%7B%5Csin%5E2A%5Ccos%5E2A%7D)
Since simplified left and right parts are the same, then the equality is true.