Simplify the expression. 2a^–4 m^5
1 answer:
We have that
Remove the negative exponent<span> by rewriting
</span>
as 
Simplify
Write 2 as a fraction with denominator 1<span>.
</span>
Multiply
and 
to get 
Write <span><span>m5</span></span><span> as a </span>fraction<span> with </span>denominator <span>1
</span>
<span>Multiply
and 
to get 
<span>
the answer is
</span><span>
</span></span>
Remove the negative exponent<span> by rewriting
</span>
Simplify
Write 2 as a fraction with denominator 1<span>.
</span>
Multiply
Write <span><span>m5</span></span><span> as a </span>fraction<span> with </span>denominator <span>1
</span>
<span>Multiply
<span>
the answer is
</span>
</span></span>
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Answer:
I'm glad you asked!
Step-by-step explanation:
So let's do it step by step.
Already she has to pay $ for going in.
She has whole pounds.
x
or
Add $ and $
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Now let's do $1.25 divided by 10.
$
divided by $
Now let's do times
x
Now let's add 7.5 to 0.5
Suppose the sides of the big triangle are called m, x and 12+4=16. We have that the big triangle and the small triangle to the right of the shape (sides x,y,12) are similar. We can take then the ratios of correponding sides and know that they will be equal. Thus, we have that 4/y=y/12. Hence, y*y=48. Thus y=
.
Answer:
0.375 feet-lb
Step-by-step explanation:
We have been given that the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb. We are asked to find the work needed to stretch the spring 6 in. beyond its natural length.
We can represent our given information as:
We will use Hooke's Law to solve our given problem.
Substituting this value in our integral, we will get:
Using power rule, we will get:
We know that 6 inches is equal to 0.5 feet.
Work needed to stretch it beyond 6 inches beyond its natural length would be
Using power rule, we will get:
Therefore, 0.375 feet-lb work is needed to stretch it 6 in. beyond its natural length.