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Lisa [10]
3 years ago
11

Margarita is hired by an accounting firm at a salary of $60,000 per year. Three years later her annual salary has increased to $

70,500. Assume her salary increase linearly. Find an equation that relates her annual salary S and the number of years t that she has worked for the firm.
Mathematics
1 answer:
agasfer [191]3 years ago
8 0

the salary was increased each by 10,500 dollars a year
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lorasvet [3.4K]
What is ur subject i would lov o help
8 0
3 years ago
IT IS TIMED PLS HELP which of the following is equivalent to (125^2/1254/3)
TEA [102]
By doing (125^2/1254/3) i get 4.15 every time i try to do it a different way, but if you do 125^(2/3) i get 25 for the answer.

answer: D) 25

hope this helped :)
3 0
3 years ago
The Marked price of an article is rupees 5000 .This price is 25% above the cost price. If the article is sold by allowing 10% di
Brilliant_brown [7]

Answer: 13%

Step-by-step explanation:

Step 1:

5000

10% of 5000=500

5% of 5000=250

25%=500+500+250= 1250 rupees

so...

5000-1250= 3750 INR, which is the original price, <u>BEFORE THE 25% WAS ADDED</u>

but..

They only want a 10% discount of the price which is 25% above the cost (5000). So essentially we want to find  15%, because 25%-10%=15%

so if...

10%=500

5%=250

15%=750 INR

this means the price with the 10% discount off 25%= 4250 INR (5000-750)

now we need to find the percentage change. For this we need to subtract the price with the 15% discount with the price BEFORE THE 25% was added

e.g 4250-3750= 500INR

Then.. divide this price with the original price before the 25% was added

e.g 500/3750= 2/15=0.13

So...

Convert 0.13 into a percentage=13%

The PERCENTAGE PROFIT of the owner is 13%

P.S Please could someone double check this answer as I am only 15 years old and may have gotten some working out wrong! Thank you

3 0
3 years ago
Write a rule for the nth term of the arithmetic sequence:<br><br> a11= 50, d = 7
ivolga24 [154]

Answer:

Required rule for n^{th} is a_{n}=7n-27.

Step-by-step explanation:

Given that,

a_{11} = 50,\  \  d=7

From the question: we have to write the n^{th} term of Arithmetic sequence.

Arithmetic Sequence or Arithmetic progression (A.P) : It is a sequence which possess that difference between of two successive sequence is always constant.

                a_{1} ,a_{2},a_{3},a_{4}.....................a_{n-1},a_{n}

                                        where, a_{1} is the first term of A.P

                                                     d is the common difference.

                                                     a_{n} is the last term or general term.

The above sequence to be in A.P then their common difference should be equal.

          d=a_{2}-a_{1} =a_{3}-a_{2}=a_{4} -a_{3} ..........................a_{n}-a_{n-1}

Now, Formula of General Term is a_{n}=a+(n-1)d

So,                                                    a_{11}= a+(11-1)d\\        a_{11} = a+10d

 Substituting the value of   a_{11} = 50,\  \  d=7 we get,

                                                         50=a+10\times7\\50=a+70\\a=-20

Then General term (a_{n}) of given data is

                                                         a_{n}=-20+(n-1)7\\a_{n}=-20+7n-7\\a_{n}=7n-27

Therefore, Required rule for n^{th} is a_{n}=7n-27.

5 0
3 years ago
Plz help will mark brainlest if right
vovangra [49]
The first arrow diagram, A, represents this relation.
4 0
2 years ago
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