Answer:
Free throws= 309 goals
Two-point field goals=341 goals
Three-point field goals=204goals
Step-by-step explanation:
This is a word problem, let us bring out all varibles
Let the number of three-point field goals =x
Two-point field goals= 2x-67
Free throws =(2x-67 )-32
Free throws =2x-67-32
Free throws =2x-99
Hence the mathematical expression for the total goals is
x+2x-67 +2x-99= 856
collecting like terms
x+2x+2x-67-99=856
5x-166=856
5x=856+166
5x=1022
divide both sides by 5 we have
x=1022/5
x=204.4
hence
1. Three-point field goals=204goals
2. Two-point field goals= 2x-67
=2(204)-67
=408-67
=341 goals
3. Free throws =2x-99
=2(204)-99
=408-99
=309 goals
