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LekaFEV [45]
4 years ago
6

My Q # 20 please help me to resolve

Mathematics
2 answers:
vekshin14 years ago
8 0

A(0) = 130

A(1) =  130 + 13x1 = 143

A(2) = 130+ 13x2 = 156

A(3) = 130+ 13x 3 = 169

answer is  A(n)=130+13n, 299

sdas [7]4 years ago
6 0

The generic equation of the arithmetic sequence is given by:

an = a1 + (n-1)d

Where,

a1: first term of the sequence

n: number of terms

d: common difference between two consecutive terms.

Therefore, substituting values we have:

an = 130 + (n-1)13

For the term number 13 we have:

an = 130 + (13-1)13

a13 = 286

Answer:

Option B

an=130 + (n-1)13, 286

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