Question

My Q # 20 please help me to resolve

Answer 1

A(0) = 130

A(1) =  130 + 13x1 = 143

A(2) = 130+ 13x2 = 156

A(3) = 130+ 13x 3 = 169

answer is  A(n)=130+13n, 299

Answer 2

The generic equation of the arithmetic sequence is given by:

$an = a1 + (n-1)d$

Where,

a1: first term of the sequence

n: number of terms

d: common difference between two consecutive terms.

Therefore, substituting values we have:

$an = 130 + (n-1)13$

For the term number 13 we have:

$an = 130 + (13-1)13$

$a13 = 286$

Answer:

Option B

$an=130 + (n-1)13, 286$