Royal Lawncare Company produces and sells two packaged products. Weedban and Greengrow. Revenue and cost information relating to the products follow: Product Weedban Greengrow Selling price per unit $ 11.00 $ 36.00 Variable expenses per unit $ 3.00 $ 14.00 Traceable fixed expenses per year $ 136.000 $ 31.000 Common fixed expenses in the company total $96.000 annually. Last year the company produced and sold 37.000 units of Weedban and 15.500 units of Greengrow. Required: Prepare a contribution format income statement segmented by product lines. Product Line Total Company Weedban Greengrow Sales Variable expenses Contribution margin Traceable fixed expenses Product line segment margin Common fixed expenses not traceable to products Net operating income
Hello!
To solve this problem, we will use a system of equations. We will have one number be x and the other y. We will use substitutions to solve for each variable.
x+y=9
x=2y-9
To solve for the two numbers, we need to solve the top equation. The second equation shows that x=2y-9. In the first equation, we can replace 2y-9 for x and solve.
2y-9+y=9
3y-9=9
3y=18
y=6
We now know the value of y. Now we need to find x. We can plug in 6 for y in the second equation to find x.
x=2·6-9
x=12-9
x=3
Just to check, we will plug these two numbers into the first equation.
3+6=9
9=9
Our two numbers are three and six.
I hope this helps!
Answer:
12870ways
Step-by-step explanation:
Combination has to do with selection
Total members in a tennis club = 15
number of men = 8
number of women = 7
Number of team consisting of women will be expressed as 15C7
15C7 = 15!/(15-7)!7!
15C7 = 15!/8!7!
15C7 = 15*14*13*12*11*10*9*8!/8!7!
15C7 = 15*14*13*12*11*10*9/7 * 6 * 5 * 4 * 3 * 2
15C7 = 15*14*13*12*11/56
15C7 = 6,435 ways
Number of team consisting of men will be expressed as 15C8
15C8 = 15!/8!7!
15C8 = 15*14*13*12*11*10*9*8!/8!7!
15C8 = 15*14*13*12*11*10*9/7 * 6 * 5 * 4 * 3 * 2
15C8 = 6,435 ways
Adding both
Total ways = 6,435 ways + 6,435 ways
Total ways = 12870ways
Hence the required number of ways is 12870ways
Answer:
Jake's error in step 3
Step-by-step explanation:
we have
Complete the square
step 1
Group terms that contain the same variable, and move the constant to the opposite side of the equation
step 2
Complete the square. Remember to balance the equation by adding the same constants to each side
step 3
Rewrite as perfect squares
Jake's error in step 3
He placed 6 instead of 3 in the left side
step 4
take square root both sides
step 5
step 6
step 7
x=5 and x=1
2x+3y= -17
5x+2y= -4
You must cancel either the x or y out to solve so i'm going to cancel the x.
-5(2x+3y= -17)
2(5x+2y= -4)
This simplifies to:
-15x -15y=85
15x+4y= -8
The -15x and 15x cancel out leaving you:
-15y=85
4y= -8
You add them top numbers by the bottom and get:
-11y=77
Then divide by -11 to get y by its self.
y= -7
Now that you know what y is just plug it in to either original problem. I will use the second one.
5x + 2(-7) = -4
5x -14 = -4
5x = 10
x = 2
So the answer is (2,-7) or x=2 and y=-7
