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dusya [7]
3 years ago
14

Using the technique in the model above, find the missing sides in this 30° 600-90 right triangle.longShort 7Hypotenuse3.571314

Mathematics
1 answer:
dalvyx [7]3 years ago
3 0
The answer to this is 14. To find the hypotenuse from the short do 2S, and for Short to Long it is S Root 3. 

Hope this helped! Please Mark as Brainliest!
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Please find question in photo below. I’m revising for a test I have in a few days, and I can’t figure this out. Please help!
Temka [501]

\large{\rm{\underline{\underline{Answer:}}}}

a) <u>n² + 6 </u>

~Here n is the number of term. So, put n = 1,2,3,4.... to get the term.

  • If n = 1, first term = 1² + 6 = 7
  • n = 2, second term = 10
  • n = 3, third temm = 15
  • n = 4, fourth term = 22
  • n = 10, tenth term = 106

b) <u>3n²</u>

  • If n = 1, first term = 3
  • n = 2, second term = 12
  • n = 3, third term = 27
  • n = 4, fourth term = 48
  • n = 10, tenth term = 300
3 0
2 years ago
3/15 as a fraction to a percent by first reducing to the lowest term
Lilit [14]
3/15 reduces to 1/5
1/5 = 0.2....0.2 * 100 = 20%
5 0
3 years ago
With the equation 2/10=4/a-3 what does a equal?
shusha [124]

Answer:

23

Step-by-step explanation:

Since 2/10 = 4/20, we know that a-3 = 20, so a = 20 + 3 = 23.

5 0
2 years ago
Please help due soon.<br><br> (No Links Allowed)
maxonik [38]

Answer: x = 5, x = -5  If you need more....

x = 5^{1}

x = \sqrt{25}

4 0
2 years ago
A family of 2 adults and 4 children is going to an amusement park. Admission is a 21 point 75 for adults and 15 point 25 for chi
Juliette [100K]

Answer:

Step-by-step explanation:

The number of adults in the family that is going to the amusement park is 2.

The number of children in the family that is going to the amusement park is 4.

Admission is a 21 point 75 for adults and 15 point 25 for children. This means that the admission cost for each adult is 21.75 and the admission cost for each adult is 15.25. Therefore,

The total cost of admission for the 2 adults would be

21.75 × 2 = 43.5

The total cost of admission for the 4 children would be

15.25 × 4 = 61

Therefore, the total cost of the families admission would be

43.5 + 61 = 104.5

7 0
3 years ago
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