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Sliva [168]
4 years ago
7

Two and four tenths times a number minus three is greater than one and six tenths times the number minus four and one tenth

Mathematics
1 answer:
diamong [38]4 years ago
8 0

Let's first turn all the words into numbers:

Two and four tenths = 2.4

One and six tenths = 1.6

Four and one tenth = 4.1

Now lets represent "a number" as x.

Then translate the wording into a linear equation:

2.4x-3>1.6x-4.1

Simplify and isolate the variable:

0.8x>-1.1

Divide by 0.8

x>1.375 or x>1 3/8

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The answer would be 6 number of pancakes. Hope it helps
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Murrr4er [49]
All the angles inside a quadrilateral add to 360 degrees.
But first, we should solve for x
Opposite angles add up to 180 degrees.
So we'll use angles B and D
x + 10 + x + 24 = 180
combine like terms
2x + 34 = 180
subtract 34 from both sides
2x = 146
divide both sides by 2
x = 73

Now let's solve for the angles
Angle D: x + 24 = 97
Angle B: x + 10 = 83
Angle A: x + 15 = 88

Opposite angles add up to 180
we know that angle A is 88
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Hope this helps!
4 0
3 years ago
What is 1+1. 100 points to whoever gets it first. Answer fast!
Anni [7]

Answer:

da answer iz two cause wen u add one plus one u get answer two

Step-by-step explanation:

let mi hope dat it useful

4 0
3 years ago
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What do you think will happen to Earth if climate chang is solved.?​
Ksju [112]

Answer:

it will be more wildfires longer periods of droughts

3 0
3 years ago
Please help me answer this question its urgent
yarga [219]

Answer:

Step-by-step explanation:

1). \frac{2}{3}n-\frac{3}{4}n+\frac{1}{6}n+2\frac{2}{9}n

= \frac{2}{3}n-\frac{3}{4}n+\frac{1}{6}n+(2+\frac{2}{9})n

= (\frac{2}{3}-\frac{3}{4}+\frac{1}{6})n+(2+\frac{2}{9})n

= (\frac{8}{12}-\frac{9}{12}+\frac{2}{12})n+(2+\frac{2}{9})n

= \frac{(8-9+2)}{12}n+(2+\frac{2}{9})n

= \frac{1}{12}n+(2+\frac{2}{9})n

= (\frac{1}{12}+2+\frac{2}{9})n

= (\frac{3}{36}+\frac{72}{36}+\frac{8}{36})n

= \frac{83}{36}n

= 2\frac{11}{36}n

2). \frac{2}{5}g-\frac{1}{6}-g+\frac{3}{10}g-\frac{4}{5}

= (\frac{2}{5}-1+\frac{3}{10})g-(\frac{1}{6}+\frac{4}{5})

= (\frac{4}{10}-\frac{10}{10}+\frac{3}{10})g-(\frac{5}{30}+ \frac{24}{30})

= (\frac{4-10+3}{10})g-(\frac{5+24}{30})

= \frac{-3}{10}g-\frac{29}{30}

= -\frac{3}{10}g-\frac{29}{30}

3). i+6i-\frac{3}{7}i+\frac{1}{3}h+\frac{1}{2}i-h+\frac{1}{4}h

= 7i-\frac{3}{7}i+\frac{1}{2}i+\frac{1}{3}h-h+\frac{1}{4}h

= (7-\frac{3}{7}+\frac{1}{2})i+(\frac{1}{3}-1+\frac{1}{4})h

= (\frac{98}{14} -\frac{6}{14}+\frac{7}{14})i+(\frac{4}{12}-\frac{12}{12}+\frac{3}{12})h

= (\frac{98-6+7}{14})i+(\frac{4-12+3}{12})h

= \frac{99}{14}i-\frac{5}{12}h

6 0
3 years ago
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