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jek_recluse [69]
3 years ago
13

The sum of two numbers is 66 and the difference is 12 . What are the numbers?

Mathematics
2 answers:
Juliette [100K]3 years ago
6 0
66-54=12. So, 54+12 = 66.
cricket20 [7]3 years ago
4 0
One of them is 27 and the other is 39
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I missed the day we learned this, please help
love history [14]

Answer:

The slope is 1/3

Step-by-step explanation:

Take 2 points on the line, lets use (0,50) and (30,60)

                                                         x1  y1           x2  y2

Use slope formula:

y2 - y1 / x2 - x1

60 - 50 / 30 - 0

10 / 30

which can be simplified to:

1/3

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2 years ago
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3 years ago
12.54 + (-24.673)<br><br><br> What’s the answer if you compute?
Zinaida [17]

Answer:

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What's the answer to the math problem 8r+4=10+2r
mart [117]
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6 0
3 years ago
If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.
Sophie [7]
There's no if about it, 

f(x)=x^3+3x^2-x-3&#10;

has a zero f(1)=0 so x-1 is a factor.   That's the special case of the Remainder Theorem; since f(1)=0 we'll get a remainder of zero when we divide f(x) by x-1.

At this point we can just divide or we can try more little numbers in the function.  It doesn't take too long to discover f(-1)=0 too, so  x+1 is a factor too by the remainder theorem.  I can find the third zero as well; but let's say that's out of range for most folks.

So far we have 

x^3+3x^2-x-3 = (x-1)(x+1)(x-r)

where r is the zero we haven't guessed yet.  Again we could divide f(x) by (x-1)(x+1)=x^2-1 but just looking at the constant term we must have

-3 = -1 (1)(-r) = r

so

x^3+3x^2-x-3 = (x-1)(x+1)(x+3)

We check f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark

We usually talk about the zeros of a function and the roots of an equation; here we have a function f(x) whose zeros are

x=1, x=-1, x=-3

8 0
3 years ago
Read 2 more answers
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